Question

A metal sphere of radius 2.0 cm carries an excess charge of 3.0 μC. What is the electric field 6.0 cm from the center of the sphere? (k = 1/4πε0 = 9.0 × 109 N ∙ m2/C2)

Answer 1

Answer:

The electric field is  $E = 7.5 *10^{6} \ N/C$

Explanation:

From the question we are told that

    The radius of the metal sphere is  $R = 2.0 \ cm = 0.02 \ m$

     The excess charge which the metal sphere carries is  $q = 3.0 \mu C = 3.0*10^{-6} \ C$

      The distance of the position being to the center is $D = 6.0 \ cm = 0.06 \ m$

       The coulomb constant is   $k =9*10^{9} \ N \cdot m^2 /C^2$

Generally the electric field is mathematically represented as  

        $E = \frac{k * q}{D^2}$

substituting values

        $E = \frac{9*10^{9} * 30.*10^{-6}}{(0.06)^2}$

      $E = 7.5 *10^{6} \ N/C$