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3 years ago

How many moles of Li3N will be created using 0.24 moles of Li in the given reaction? 6Li + N2 2Li3N

2 answers:

7 0

6 Li + N2 = 2 Li3N

6 moles Li ---------> 2 moles Li3N
0.24 moles Li ------> ?

moles Li3N = 0.24 * 2 / 6

= 0.48 / 6

= 0.08 moles of li3N

hope this helps!.

Pepsi [2]3 years ago

7 0

Answer : The number of moles of $Li_3N$ will be, 0.08 moles

Solution : Given,

Moles of Li = 0.24 mole

The given balanced chemical reaction is,

$6Li+N_2\rightarrow 2Li_3N$

From the balanced reaction, we conclude that

As, 6 moles of Li react to gives 2 moles of $Li_3N$

So, 0.24 moles of Li react to gives $\frac{2}{6}\times 0.24=0.08$ moles of $Li_3N$

Therefore, the number of moles of $Li_3N$ will be, 0.08 moles

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eduard

Answer: The answer is B

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5 0

3 years ago

When 3.93 grams of lactic acid, CHoOs(s), are burned in a bomb

aliya0001 [1]

The heat released in the combustion of lactic acid is absorbed by the

calorimeter and in the decomposition of the lactic acid.

ΔH°f of lactic acid is approximately -716.2 kJ

Reasons:

Known parameters are;

Mass of the lactic acid = 3.93 grams

Heat capacity of the bomb calorimeter = 10.80 kJ·K⁻¹

Change in temperature of the calorimeter, ΔT = 5.34 K

ΔHrxn = ΔErxn

ΔH°f of H₂O(l) = -285.8 kJ·mol⁻¹

ΔH°f of CO₂(g) = -393.5 kJ·mol⁻¹

The chemical equation for the reaction is presented as follows;

C₃H₆O₃ + 2O₂ → 3CO₂ + 3H₂O

The heat of the reaction = 10.80 kJ·K⁻¹ × 5.34 K = 57.672 kJ

Molar mass of C₃H₆O₃ = 90.07 g/mol

Number of moles of C₃H₆O₃ = $\dfrac{3.93 \, g}{90.07 \, g/mol}$ = 0.043633 moles

Number of moles of CO₂ produced = 3 × 0.043633 moles = 0.130899 moles

Heat produced = 0.130899 mole × -285.8 kJ·mol⁻¹ = -37.4109342 kJ

Moles of H₂O produced = 0.130899 moles

Heat produced = 0.130899 mole × -393.5 ≈ -51.51 kJ

Therefore, we have;

Heat absorbed by the lactic acid = ΔH°f of H₂O + ΔH°f of CO₂ + Heat absorbed by the calorimeter

Which gives;

Heat absorbed by lactic acid = -37.4109342 kJ - 51.51 kJ + 57.672 kJ ≈ -31.249 kJ

The heat absorbed by the lactic acid ≈ -31.249 kJ

$\Delta H^{\circ}f \ of \ C_3H_6O_3 = \dfrac{-31.249}{0.043633} \approx -716.2$

ΔH°f of C₃H₆O₃ ≈ -716.2 kJ

Heat of formation of lactic acid ≈ -716.2 kJ.

Learn more here:

brainly.com/question/13185938

5 0

3 years ago

1 point

ladessa [460]

Answer: q=64 kJ

Hope this helps

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-Carrie

P.S. It would mean a lot if you marked brainliest 

5 0

4 years ago

Rachel burns a 53 gram cracker under a soda can filled with 81.6 grams of water. She took the temperature of the water before sh

Anna11 [10]

Answer

Q=4479.8 cal

Procedure

To solve the problem you will need to use the specific heat formula

$Q=mc\Delta T$

Where;

Q=heat energy

m=mass

c=specific heat capacity

ΔT=change in temperature

Assuming that the heat released from the cracker of unknown material is equal to the heat absorbed by the water, then we can use the c and m for water in our calculations.