Question

How many moles of Li3N will be created using 0.24 moles of Li in the given reaction? 6Li + N2 2Li3N

Answer 1

6 Li + N2 =  2 Li3N

6 moles Li ---------> 2 moles Li3N
0.24 moles Li ------>  ?

moles Li3N =  0.24 * 2 /  6

=  0.48 / 6 

= 0.08 moles of li3N

hope this helps!.

Answer 2

Answer : The number of moles of $Li_3N$ will be, 0.08 moles

Solution : Given,

Moles of Li = 0.24 mole

The given balanced chemical reaction is,

$6Li+N_2\rightarrow 2Li_3N$

From the balanced reaction, we conclude that

As, 6 moles of Li react to gives 2 moles of $Li_3N$

So, 0.24 moles of Li react to gives $\frac{2}{6}\times 0.24=0.08$ moles of $Li_3N$

Therefore, the number of moles of $Li_3N$ will be, 0.08 moles