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Ilya [14]
3 years ago
11

Bromine and nitrogen combine to form nitrogen tribromide (NBr3). How many liters of NBr3 gas are produced when 6.85 L of bromine

reacts with excess nitrogen? Assume conditions are at STP.
Chemistry
1 answer:
dlinn [17]3 years ago
7 0

Answer:

4.567 ltr

Explanation:

both are gases

so

N2 +Br2 =NBr3

balancing

N2 +3B2 = 2 NBr3

now

3 litr of B2 gives 2 liter of NBr3

6.85 litr of B2 gives 2/3 *6.85 litr NBr3 = 4.567ltr

You might be interested in
Key terms: Reset ____________ anions are strong nucleophiles that open epoxide rings by an SN2 mechanism. ____________ tautomers
iogann1982 [59]

Answer:

Acetylide , Enol ,aldehydes, tautomers, alkynes , Hydroboration, Keto

Explanation:

Reset <u>Acetylide</u>  anions are strong nucleophiles that open epoxide rings by an SN2 mechanism. <u>Enol </u>tautomers have an O-H group bonded to a C=C. <u>aldehydes </u>are formed from terminal alkynes with the addition of water using BH3 then H2O2. <u>tautomers</u> are constitutional isomers that differ in the location of a double bond and a hydrogen and exist in an equilibrium with each other. <u>alkynes</u> are compounds that contain a carbon-carbon triple bond. <u>Hydroboration</u> of a terminal alkyne adds BH₂ to the less substituted, terminal carbon.<u> Keto</u> tautomers have a C=O and an additional C-H bond.

3 0
3 years ago
What is the concentration in g/L of a solution containing 10 g of solute in 2 L of solution
alekssr [168]

The concentration is 5 g/L.

Concentration = mass/volume = 10 g/2 L = 5 g/L

6 0
3 years ago
A gardener decides to use only part of their garden in the spring. What will most likely happen first in the unused part of the
Gemiola [76]

Answer:

Growth of weeds and grasses

Explanation:

The part of the garden, probably left to rest by the Gardner, would start experiencing a legion of invasive plants. Giant weeds and grasses could be seen, and brambles and tree seedlings could also sneak in.  

Some Gardeners would recommend the use of herbicides to restore order to an abandoned garden even though certain scientists are of the opinion that chemicals may not offer a sound solution to the problem.  

6 0
3 years ago
Which one of the following statements is not true concerning 2.00 L of a 0.100 M solution of Ca3(PO4)2?
Len [333]

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .......(1)

  • <u>For A:</u>

Molarity of calcium phosphate solution = 0.100 M

Volume of solution = 2.00 L

Putting values in equation 1, we get:

0.100M=\frac{\text{Moles of }Ca_3(PO_4)_2}{2.00}\\\\\text{Moles of }Ca_3(PO_4)_2=(0.100mol/L\times 2.00L)=0.200mol

Moles of calcium phosphate = 0.200 moles

  • <u>For B:</u>

1 mole of calcium phosphate contains 3 moles of calcium atoms, 2 moles of phosphate atoms and 8 moles of oxygen atoms.

So, 0.200 moles of calcium phosphate will contain = (8\times 0.200)=1.6 moles of oxygen atoms.

Moles of oxygen atoms = 1.6 moles

  • <u>For C:</u>

Molarity of calcium phosphate solution = 0.100 M

Volume of solution = 1.00 L

Putting values in equation 1, we get:

0.100M=\frac{\text{Moles of }Ca_3(PO_4)_2}{1.00}\\\\\text{Moles of }Ca_3(PO_4)_2=(0.100mol/L\times 1.00L)=0.100mol

Moles of calcium ions = (0.100\times 3)=0.300 moles

  • <u>For D:</u>

Molarity of calcium phosphate solution = 0.100 M

Volume of solution = 5.00 L

Putting values in equation 1, we get:

0.100M=\frac{\text{Moles of }Ca_3(PO_4)_2}{5.00}\\\\\text{Moles of }Ca_3(PO_4)_2=(0.100mol/L\times 5.00L)=0.500mol

Moles of phosphorus atoms = (0.500\times 2)=1.00 moles

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of atoms

Number of phosphorus atoms in 0.500 moles of calcium phosphate will be = (1.00\times 6.022\times 10^{23})=6.022\times 10^{23}

  • <u>For E:</u>

1 mole of calcium phosphate contains 3 moles of calcium ions and 2 moles of phosphate ions.

So, 0.200 moles of calcium phosphate will contain = (3\times 0.200)=0.600 moles of calcium ions

Moles of calcium ions = 0.600 moles

Hence, the correct answer is Option B.

6 0
3 years ago
PLEASE HELP!
QveST [7]

Answer:

1) Increasing the pressure          A) Shift to the left  

2) Removing hydrogen gas        B) Shift to the right    

3) Adding a catalyst                     C) No effect

Explanation:

  • <em>Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>

<em></em>

<u><em>1) Decreasing the pressure:</em></u>

  • When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
  • The reactants side (left) has 4.0 moles of gases and the products side (right) has 2.0 moles of gases.
  • So, decreasing the pressure will shift the reaction to the side with more moles of gas (left side).

<u><em>so, the right match is: A) Shift to the left.</em></u>

<em><u>2) Adding hydrogen gas:</u></em>

  • Adding hydrogen gas will increase the concentration of the reactants side, so the reaction will be shifted to the right side to suppress the increase in the concentration of hydrogen gas by addition.

<u><em>so, the right match is: B) Shift to the right.</em></u>

<u><em></em></u>

<u><em>3) Adding a catalyst:</em></u>

  • Catalyst increases the rate of the reaction without affecting the equilibrium position.
  • Catalyst increases the rate via lowering the activation energy of the reaction.
  • This can occur via passing the reaction in alternative pathway (changing the mechanism).
  • The activation energy is the difference in potential energies between the reactants and transition state (for the forward reaction) and it is the difference in potential energies between the products and transition state (for the reverse reaction).
  • in the presence of a catalyst, the activation energy is lowered by lowering the energy of the transition state, which is the rate-determining step, catalysts reduce the required energy of activation to allow a reaction to proceed and, in the case of a reversible reaction, reach equilibrium more rapidly.
  • with adding a catalyst, both the forward and reverse reaction rates will speed up equally, which allowing the system to reach equilibrium faster.

<u><em>so, the right match is: B) No effect.</em></u>

<u><em></em></u>

5 0
3 years ago
Read 2 more answers
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