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Kryger [21]
3 years ago
14

Which group and period does the electron figuration represent 1s22s22p63s24s23d8

Chemistry
1 answer:
taurus [48]3 years ago
5 0

<em>grou</em><em>p</em><em> </em><em>4</em><em> </em><em>,</em><em> period</em><em> </em><em>4</em>

Explanation:

from the electron configuration,

the element is Titanium

and it's has 22 electrons on it's shells , so wen you place it on the periodic table, you will see that it's in group 4 period 4

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Identify the conjugate base in each pairs
DiKsa [7]

Answer: 1) RCOO^-

2) H_2PO_4^-

3) RNH_2

4) HCO_3^-

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

1) RCOOH\rightarrow RCOO^-+H^+

Here, RCOOH is loosing a proton, thus it is considered as an acid and after losing a proton, it forms RCOO^- which is a conjugate base.

2) H_3PO_4\rightarrow H_2PO_4^-+H^+

Here, H_3PO_4 is loosing a proton, thus it is considered as an acid and after losing a proton, it forms H_2PO_4^- which is a conjugate base.

3) RNH_3^+\rightarrow RNH_2+H^+

Here, RNH_3^+ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms RNH_2 which is a conjugate base.

4) H_2CO_3\rightarrow HCO_3^-+H^+

Here, H_2CO_3 is loosing a proton, thus it is considered as an acid and after losing a proton, it forms HCO_3^- which is a conjugate base.

8 0
3 years ago
The table compares the final cost of
Snowcat [4.5K]

Answer:

y = -2.5 + x

Explanation:

Given the data:

__X____Y

$20 __$17.50

$21 __ $18.50

$22__ $19.50

$23__ $20.50

Using a linear regression calculator :

The linear regression model obtained is :

y = -2.5 + x

Where ; - 2.5 = intercept ; gradient / slope = 1

3 0
3 years ago
4. How does the water vapor change as altitude increases?
Karolina [17]

Answer:

it drifts through the atmosphere and the vapor absorbs heat then the warm air rises up therefore leaving the planet's surface and releasing the heat back into the upper part of the atmosphere

4 0
3 years ago
A 3.20-mol sample of gas occupies a volume of 350. mL at 300.0 K. Determine the
nalin [4]

Answer:

P \approx 225atm

Explanation:

From the question we are told that:

Moles of sample n=3.20_mol

Volume V=350mL

Temperature T=300k

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 P=\frac{nRT}{V}

 P=\frac{3.20*0.08206*300}{350*10^{-3}}

 P=225.079atm

 P \approx 225atm

4 0
3 years ago
As you have seen in this lab, the density of water is near 1 g/cm3. Anything with a density lower than this will float in water,
hammer [34]
The third answer is the one you want. You have to have an adjustable density. All other things being equal, if the tanks you use for holding just water when filled with water will let the sub sink, because the sub is made of a dense metal like iron or steel.

If on the other hand you fill these tanks with air, the net density will be below one and the sub will rise.
8 0
3 years ago
Read 2 more answers
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