Question

Determine the total condensation rate of water vapor onto the front surface of a vertical plate that is 10 mm high and 1 m in the horizontal direction. The plate is exposed to saturated steam at atmospheric pressure and is maintained at 75oC.

Answer 1

Answer:

Q =  63,827.5 W

Explanation:

Given:-

- The dimensions of plate A = ( 10 mm x 1 m )

- The fluid comes at T_sat , 1 atm.

- The surface temperature, T_s = 75°C  

Find:-

Determine the total condensation rate of water vapor onto the front surface of a vertical plate

Solution:-

- Assuming drop-wise condensation the heat transfer coefficient for water is given by Griffith's empirical relation for T_sat = 100°C.

                            h = 255,310 W /m^2.K

- The rate of condensation (Q) is given by Newton's cooling law:

                           Q = h*As*( T_sat - Ts )

                           Q = (255,310)*( 0.01*1)*( 100 - 75 )

                           Q =  63,827.5 W

Answer 2

Answer:

Q =  63,827.5 W

Explanation:

From the questions given, we recall the following,

The dimensions of  vertical plate A = ( 10 mm x 1 m )

The fluid comes at T_sat, 1 atm.

The surface temperature pressure maintained  T_s = 75°C  

Thus we determine,

The total  rate of condensation of water vapor onto the front surface of a vertical plate

Assuming drop-wise condensation the heat transfer coefficient for water is given by

Griffith's empirical relation for T_sat = 100°C.

Then

           h = 255,310 W /m^2.K

The rate of condensation (Q) is stated  by Newton's cooling law:

          Q = h x As x ( T_sat - Ts )

          Q = (255,310)x ( 0.01 x 1)x ( 100 - 75 )

Therefore

            Q =  63,827.5 W