When you squish the spring, you put some energy into it, and after the cord
burns and they go boing in opposite directions, that energy that you stored
in the spring is what gives the blocks their kinetic energy.
But linear momentum still has to be conserved. It was zero while they were
tied together and nothing was moving, so it has to be zero after they both
take off.
Momentum = (mass) x (velocity)
After the launch, the 5.5-kg moves to the right at 6.8 m/s,
so its momentum is
(5.5 x 6.8) = 37.4 kg-m/s to the right.
In order for the total momentum to be zero, the other block has to
carry the same amount of momentum in the opposite direction.
M x V = (6 x speed) = 37.4 kg-m/s to the left.
Divide each side by 6 : Speed = 37.4 / 6 =<em> 6.2333... m/s left</em>
(That number is (6 and 7/30) m/s .)
Answer:
Secondary current is 8A
Explanation:
Data :
Primary supply = Vp = 240 V
Secondary supply = Vs = 60V
Primary current = Ip = 2A
Secondary current = Is = ?
Formula : Vp × Ip = Vs × Is
So for secondary current formula becomes
Is = (Vp/Vs)×Ip = (240/60) × 2
Is = 4 × 2 = 8A
I think cardiac muscle would make up the heart because it’s able to pump blood through the heart and the rest of the body.
<span>here we have to apply the right hand rule
no, since the magnetic field is perpendicular with respect to the direction of the current</span>
It would be D) the rope is pulled to the right. This is because their is a greater force in that direction.
