A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times }{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

moles of $BaCl_2$ (solute) = $\frac{\text {given mass}}{\text {Molar Mass}}=\frac{110g}{208g/mol}=0.529mol$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.529\times 1000}{440ml}=1.20mole/L$

Therefore, the molarity of solution is 1.20 mol/L

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