From that graph of the force of the sun on a comet, you can see that the force increases as the distance decreases. (A)
Answer: its speed upon release is 26.05 m/s
Explanation:
Given that;
mass m = 0.244 kg
force F = 30.3 N
V1 = 14.7 m/s
r = 59.3 cm = 0.593 m
Vf = ?
we know that;
1/2mV1² + FπR = 1/2mVf²
so we substitute
[1/2×0.244×(14.7)²] + [30.3×π×0.593 = 1/2×0.244×Vf²
26.3629 + 56.4478 = 0.122Vf²
82.8107 = 0.122Vf²
Vf² = 82.8107 / 0.122Vf
Vf² = 678.7762
Vf = √678.7762
Vf = 26.05 m/s
Therefore its speed upon release is 26.05 m/s
Answer:
30) B; To analyze this question, recall the equation for Doppler, Δf/f = v/c. This demonstrates that the change in frequency is directly proportional to the relative velocity. If the acceleration is constant, the velocity is changing at a constant rate, so anything directly proportional to that must be changing at a constant rate. Because no squares or roots are involved, it must be linear, not exponential, making B the best answer.
Explanation:
Answer:
The horizontal component of the truck's velocity is: 23.70 m/s
The vertical component of the truck's velocity is: 3.13 m/s
Explanation:
You have to apply trigonometric identities for a right triangle (because the ramp can be seen as a right triangle where the speed is the hypotenuse), in order to obtain the components of the velocity vector.
The identities are:
Cosα=
Senα=
Where H is the hypotenuse, α is the angle, CA is the adjacent cathetus and CO is the opposite cathetus
The horizontal component of the truck's velocity is:
Let Vx represent it.
In this case, CA=Vx, H=24 and α=7.5 degrees
Vx=(24)Cos(7.5)
Vx=23.79 m/s
The vertical component of the truck's velocity is:
Let Vy represent it.
In this case, CO=Vy, H=24 and α=7.5 degrees
Vy=(24)Sen(7.5)
Vy=3.13 m/s
EPE= 0.5 * spring constant * (extension)^2
Spring constant=EPE/0.5*extension^2
5J/0.5*0.5^2
=40N/m