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bulgar [2K]
3 years ago
7

Which information did the Glomar Challenger study in 1968?

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0
-Glomar Challenger studies about the "age of rocks in various places in the ocean" in 1968.

(Glomar Challenger was a "deep sea research vessel" for marine geology and oceanography studies)

hope this helps!! :))
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que tiempo tarda juan en su carro al llegar al trabajo si lleva una velocidad de 25 m/s a una distancia de 5m
kramer

Answer:

0.2s

Explanation:

Given parameters:

Speed  = 25m/s

Distance  = 5m

Unknown:

Time taken for Juan to get to his work  = ?

Solution:

To solve this problem we use the relationship below:

 

   Speed  = \frac{distance}{time}  

  Time  =  \frac{distance }{speed}  

So;

   Time  = \frac{5}{25}   = 0.2s

4 0
3 years ago
The dark bands on the wall are from ______________ interference. and i will give brainlyest
Fittoniya [83]
Light can be seen as an electromagnetic wave.
What happens when two waves, with the same frequency, superpose is called interference.

If at a certain point two waves arrive both with a crest, we have constructive interference and the amplitudes sum up, reaching the maximum value, resulting in bright spots.

If at a certain point one of the waves arrives with a crest and the other wave arrives with a trough, we have destructive interference, and the two amplitudes cancel out, resulting in dark spots.

Therefore, t<span>he dark bands on the wall are from destructive interference.</span>
4 0
4 years ago
Choose a sport you like, such as football or track Describe how a high level of flexibility would affect your performance in tha
irinina [24]

Answer:

Swimming

Explanation:

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Brainlist pls!

6 0
3 years ago
Read 2 more answers
What is the Underground water
Semmy [17]

Answer:

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7 0
3 years ago
An object is projected upward from the surface of the earth with an initial speed of 3.7 km/s. find the maximum height it reache
Mariulka [41]
The kinetic energy of the object just after it starts its motion from the Earth surface is
K= \frac{1}{2}mv^2
where m is the object mass and v=3.7 km/s=3700 m/s its initial speed.
When it reaches its maximum height, the object speed is zero and all its kinetic energy converted into gravitational potential energy, which is
U=mgh
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Since the energy of the object must be conserved, K=U, therefore we can write
\frac{1}{2}mv^2 =mgh
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5 0
4 years ago
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