Power of the lamp = (voltage) x (current)
0.62 watt = (3.0 v) x (current)
Current = (0.62 watt) / (3.0 volt)
Current = 0.207 Ampere
Charge = (current) x (time)
Charge = (0.207 Amp) x (0.32 sec)
<em>a). Charge = 0.066 Coulomb</em>
Energy discharge through the lamp = (charge) x (voltage)
Energy = (0.66 C) x (3.0 volt)
Energy = 0.1984 Joule
Energy stored in a capacitor = (1/2) (Capacitance) (voltage²)
0.1984 Joule = (1/2) (Cap) (3.0 v)²
Cap = 2 x 0.1984 / 9
<em>b). Cap = 0.044 Farad</em> (yikes !)
Resistance of the lamo = (voltage) / (current)
Resistance = (3.0 volt) / (0.207 Amp)
<em>c). Resistance = 14.49 Ω</em>
All of this feels OK except for that ridiculous 44,000 μF, 3v capacitor. Sadly, I have checked my work without finding an error, and I am too lazy to check it again. So I'll call this my final answer, and leave it to some better Brainly person to find where I went wrong.
