Answer:
mercury
arsenic
ricin
ddt
Explanation:
pls mark me as brainliest
Here volume of gas is not given so question is solved assuming volume as 1 L.
The number of moles of 1 L gas present in the sealed container at a
pressure of 125 kPa at 25 degrees Celsius is 0.0067 moles.
The ideal gas law equation can be written as
PV = nR T
Here
P is the pressure of the gas in atm
V is the volume it occupies in L
n is the number of moles of gas present in the sample
R is the universal gas constant, equal to 0.0821 atm L/ mol K
T is the absolute temperature of the gas in Kelvin
Now, it's important to realize that the units you have for the volume, pressure, and temperature of the gas must match the unit used in the expression of the universal gas constant.
So
P = 125 kPa
1 atm = 760 kPa
P = 125/760 = 0.1644 atm
T = 25 degree celsius = 25 +273 = 298 K
Taking V = 1 L
So
n = PV/RT
n = 0.1644 x 1 / 0.0821 x 298
n = 0.0067 moles
To learn more about the ideal gas law, please click on the link brainly.com/question/128737528
#SPJ9
#14 isn't really a Physics problem. It's more of just reading a graph.
A). When speed changes, acceleration is
(change in speed) / (time for the change) .
To be correct about it, acceleration can be positive ... when speed
is increasing ... or it can be negative ... when speed is decreasing.
So, on this graph, there are two periods of acceleration:
From zero to 2 seconds, acceleration = (8 m/s) / (4 sec) = 2 m/s² .
From 10 to 12 seconds, acceleration = (-4 m/s) / (2 sec) = -2 m/s² .
B). From 12 to16 seconds, you can read the speed right from
the graph. It's 4 m/s .
C). From 2 to 10 seconds, the objects speed is a steady 8 m/s.
Covering 8 m/s every second for 8 seconds, it covers 64 meters.
Do you remember that distance is the area under the speed/time
graph? You can see that plainly on this graph. From 2 to 10 sec,
there are 16 blocks. Each block is (2 m/s) high and (2 sec) wide,
so its area is (2 m/s) x (2 sec) = 4 meters. The area of 16 blocks
is (16) x (4 meters) = 64 meters.
====================================
#15.
a). constant velocity on a distance graph is a line that slopes up;
constant velocity on a velocity graph is a horizontal line;
b). positive constant acceleration on a distance graph is a
line that curves up;
positive constant acceleration on a velocity graph is a
straight line that slopes up;
c). "uniformly slowing down to a stop" on a distance graph
is a line that's less and less curved as time goes on, and
eventually reaches the x-axis.
"uniformly slowing down to a stop" on a velocity graph is
a straight line that slopes down, and stops when it reaches
the x-axis.
Answer:
"we both attract each other with the same force but we know that attraction between two bodies depends upon their mass, greater the mass of two bodies is the force of attraction between them"(got this off the internet).
