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3 years ago

Which statements accurately describe the greenhouse effect? Check all that apply.

Chemistry

2 answers:

lana [24]3 years ago

8 0

Answer:

B C E

Explanation:

Did the test

Troyanec [42]3 years ago

8 0

Answer:

B C F

Explanation:

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The cell potential of the following electrochemical cell depends on the gold concentration in the cathode half-cell: Pt(s)|H2(g,

Masja [62]

Answer: The concentration of $Au^{3+}$ in the solution is $1.87\times 10^{-14}M$

Explanation:

The given cell is:

$Pt(s)|H_2(g.1atm)|H^+(aq.,1.0M)||Au^{3+}(aq,?M)|Au(s)$

Half reactions for the given cell follows:

Oxidation half reaction: $H_2(g)\rightarrow 2H^{+}(1.0M)+2e^-;E^o_{H^+/H_2}=0V$ ( × 3)

Reduction half reaction: $Au^{3+}(?M)+3e^-\rightarrow Au(s);E^o_{Au^{3+}/Au}=1.50V$ ( × 2)

Net reaction: $3H_2(s)+2Au^{3+}(?M)\rightarrow 6H^{+}(1.0M)+2Au(s)$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=1.50-0=1.50V$

To calculate the concentration of ion for given EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[H^{+}]^6}{[Au^{3+}]^2}$

where,

$E_{cell}$ = electrode potential of the cell = 1.23 V

$E^o_{cell}$ = standard electrode potential of the cell = +1.50 V

n = number of electrons exchanged = 6

$[Au^{3+}]=?M$

$[H^{+}]=1.0M$

Putting values in above equation, we get:

$1.23=1.50-\frac{0.059}{6}\times \log(\frac{(1.0)^6}{[Au^{3+}]^2})$

$[Au^{3+}]=1.87\times 10^{-14}M$

Hence, the concentration of $Au^{3+}$ in the solution is $1.87\times 10^{-14}M$

7 0

3 years ago

A student wants to measure the entropy of ice. What should the student do?

Helen [10]

Answer: Option (c) is the correct answer.

Explanation:

Entropy is defined as the degree of randomness. This means that more is the number of collisions taking place between atoms of a substance more will be the randomness.

Therefore, more will be the entropy of substance. We cannot measure the entropy but we can measure the change in entropy of a substance.

A thermometer is a glass tube that contains a liquid column generally mercury, and it is usually used to measure the temperature of human body.

A calorimeter is a device or apparatus that is used in a chemical reaction to measure the amount of heat involved.

Therefore, we can conclude that the student can't measure entropy directly, only an entropy change.

6 0

3 years ago

Silver sulfate dissociates into silver ions and sulfate ions:

bagirrra123 [75]

Answer:

A its a step by step equation the answer is A

7 0

3 years ago

A metal pellet with a mass of 100.0 g, originally at 116°C, is dropped into a cup of water, initially at

Alina [70]

Answer:

C, 42g

Explanation:

In thermal equilibrium, both bodies (metal pellet and water) both have the same final temperature (46.3°C).

Assuming no heat is lost to surroundings,

the energy lost from metal pellet = energy gained for water

Since E = mc∆T

(energy = mass x specific heat capacity x temperature change)

mc∆T (metal pellet) = mc∆T (water)

100 x 0.568 x (116-46.3) = m 4.184 (46.3 - 23.8)

3958.96 = 94.14m

m = 42g

6 0

3 years ago

5. Which of the following can be classified as a mixture ?

podryga [215]

5. B air is a mixture of many elements, but is not a chemically fused.

6. B Beef stew, composition varies throughout.

7. A. They can be chemically separated into their component elements, but they are all homogenous, and as such, have constant composition, which differs from the components properties, as the components must undergo a chemical change to become compounds.

5 0

3 years ago