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3 years ago

9

Gases in the atmosphere that trap solar energy

2 answers:

Korolek [52]3 years ago

7 0

Answer:

d

Explanation:

A greenhouse gas (sometimes abbreviated GHG) is a gas that absorbs and emits radiant energy within the thermal infrared range. Greenhouse gases cause the greenhouse effect on planets. The primary greenhouse gases in Earth's atmosphere are water vapor (H. 2O), carbon dioxide (CO. 2), methane (CH.

nalin [4]3 years ago

6 0

D greenhouse gases is a gas that is trapped in the solar energy

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Which system allows for the continuation of the species? Explain the importance of the immune system.

seropon [69]

Answer:

1 the reproductive system. and the immune system is there to fight off any viruses or bacteria that had entered your body. If the bacteria is harmful it will be fought.

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3 years ago

Read 2 more answers

You have 50 ml of a complex mixture of weak acids that contains some HF (pKa = 3.18) and some HCN (pKa = 9.21). Which is larger,

bonufazy [111]

Answer:

$\frac{[F^{-}]}{[HF]}$ is larger

Explanation:

$pK_{a}=-logK_{a}$ , where $K_{a}$ is the acid dissociation constant.

For a monoprotic acid e.g. HA, $K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}$ and $\frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}$

So, clearly, higher the $K_{a}$ value , lower will the the $pK_{a}$

In this mixture, at equilibrium, $[H^{+}]$ will be constant.

$K_{a}$ of HF is grater than $K_{a}$ of HCN

Hence, $(\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})$

So, $\frac{[F^{-}]}{[HF]}$ is larger

5 0

3 years ago

Which of the following best describes a covalent bond?

Free_Kalibri [48]

Answer:

A covalent bond involves two nonmetals that share electrons.

Explanation:

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2 years ago

The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m

monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

= 130 x $10^{-12}$ m

The diameter of a vanadium atom = 2 x radius

= 2 x 130 x $10^{-12}$

= 260 x $10^{-12}$ m

Given a distance of 1.30 mm = 1.30 x $10^{-3}$ m,

The number of vanadium atoms required to span the distance = $\frac{1.3*10^{-3} }{260*10^{-12} }$

= 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0

3 years ago

Please help me whoever does help me gets 16 points just please help me

Citrus2011 [14]

Answer:

The answer is A.

4 0

3 years ago