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3 years ago

Which statements about velocity are true?

2 answers:

4 0

A, B, and D are true for sure. It's possible that C might also be true, if we only knew what the last word or symbol is supposed to be.

Softa [21]3 years ago

3 0

just took the quiz its A C and B

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Think about a situation at school where you or someone you know

Diano4ka-milaya [45]

Answer:

to have courage and show the strength of your character. ... A person with true grit has passion and perseverance. Goals are set and followed through.

Explanation:

for example: i had the passion and the courage to finish my school work and chores for i can go out with my friends and to get out of the house for a bit and have fun so i had the courage to finish chores from the house and do some schoolwork for i can finish ad hang out with some friends. so i had the strength to finish everything because i didn't want to be doing school work and chores any more so i had the passion to finish up quickly

6 0

3 years ago

Please help with my finals

allsm [11]

the answer is the speed of blue ball after collision is 2.6v

6 0

3 years ago

Read 2 more answers

For each star, determine how its light would be shifted. Not all choices may be used, and some may be used more than once. A red

barxatty [35]

Answer:

Explanation:

To calculate the red shift you use the following formula:

$z=\frac{1+vcos\theta/c}{\sqrt{1-v^2/c^2}}-1$

\tetha: angle between the observer and the motion of the body

v: speed of the body

c: speed of light

for motion with angle 90° (transversal motion):

$z=\sqrt{\frac{c+v}{c-v}}-1$

- A red dwarf moving away from Earth at 39.1 km/s :

$z=\sqrt{\frac{3*10^8m/s+39.1*10^3m/s}{3*10^8m/s-39.1*10^3m/s}}-1=1.3*10^{-4}$

- A yellow dwarf moving transversely at 15.1 km/s (angle = 90°):

$z=\frac{1+0}{\sqrt{1-(15.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.27*10^{-9}$

- A red giant moving towards Earth at 23.3 km/s (angle = 0°):

$z=\frac{1+(23.3*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(23.3*10^3m/s)^2/(3*10^8m/s)^2}}-1=7.76*10^{-5}$

- A blue dwarf moving away from Earth at 25.9 km/s $z=\frac{1+(25.9*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(25.9*10^3m/s)^2/(3*10^8m/s)^2}}-1=8.63*10^{-5}$

- A red dwarf moving transversely at 14.1 km/s

$z=\frac{1+0}{\sqrt{1-(14.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.11*10^{-9}$

6 0

4 years ago

1. Describe the differences in the ways the sand castle is changed by an ocean wave and by Dylan stomping on it

Snezhnost [94]

A sand castle that was changed by the ocean waves would be slowly taken away from by the waves and would just become a smooth mound of sand. If Dylan stomped on it then it would still have all of the same sand as before but in a different shape. It would also become a mound of sand but it would have all the same sand as before.

(I don't know if I was supposed to talk about fancy physics stuff so I just gave a basic explanation. I don't know if my answer is really right or not... hope it helped though :))

6 0

3 years ago

Please help meeeeeeeeeeeeeeeee

Julli [10]

I can't see the answers clearly, but I can see the question. So, I'll just give you a clue/hint.

A stars brightness actually depends on how far it is from your location. If it's far away, it will be dimmer than its counterpart that is closer. To summarize it, if two stars have the same brightness level and one is farther away than the other, the one farther away will appear dimmer than its closer counterpart.

5 0

3 years ago