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BlackZzzverrR [31]
3 years ago
13

An atom that has 84 protons and 86 neutrons undergoes a reaction. At the end of the reaction, it has 82 protons and 84 neutrons.

What happened to the atom?
Physics
2 answers:
Pepsi [2]3 years ago
8 0

Answer: The atom undergoes alpha decay.

Explanation: An atom has 84 protons and 86 neutrons initially. When this atom undergoes a reaction the product obtained has 82 protons and 84 neutrons.

As the product obtained has 2 protons less and 2 neutrons less which means that the mass number is decreased by 4 units and atomic number is reduced by 2 units.

The atom undergoes an alpha-decay because in this decay the particle emitted is alpha particle which has an atomic number of 2 and atomic mass of 4 units.

Equation follows:

_{84}^{170}\textrm{X}\rightarrow _{82}^{166}\textrm{Y}+_2^4\alpha

The atom which is undergoing alpha decay is Polonium (Po) and the product formed is Lead (Pb).

Tju [1.3M]3 years ago
4 0
Hi! the atom in this particular problem has emitted an alpha particle in a nuclear reaction. 

Glad I could help, and happy learning!
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This is due to an increase in hydrostatic pressure, the force per unit area exerted by a liquid on an object. The deeper you go under the sea, the greater the pressure of the water pushing down on you. For every 33 feet (10.06 meters) you go down, the pressure increases by one atmosphere .

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If a man weight 155 lb on earth, specify
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What is the equivalent resistance for a series circuit with three resistors : 5.0 ohms, 2.0 ohms, and 12.0 ohms
vesna_86 [32]

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8 0
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A tennis player swings her 1000 g racket with a speed of 11 m/s. She hits a 60 g tennis ball that was approaching her at a speed
shusha [124]

Answer:

- 3.72 Ns.

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Explanation:

mass of racket, M = 1000 g = 1 kg

mass of ball, m = 60 g = 0.06 kg

initial velocity of racket, U = 11 m/s

initial velocity of ball, u = 18 m/s

final velocity of ball, v = - 44 m/s

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(a) Momentum is defined as the product of mass and velocity of the ball.

initial momentum of the ball = m x u = 0.06 x 18 = 1.08 Ns

Final momentum of the ball = m x v = 0.06 x (- 44) = - 2.64 Ns

Change in momentum of the ball = final momentum - initial momentum

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Thus, the change in momentum of the ball is - 3.72 Ns.

(b) By use of conservation of momentum

initial momentum of racket and ball = final momentum of racket and ball

1 x 11 + 0.06 x 18 =  1 x V - 0.06 x 44

12.08 = V - 2.64

V = 9.44 m/s

Thus, the final velocity of the racket afetr the impact is 9.44 m/s .

3 0
3 years ago
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