A 1451 kg car is traveling at 48.0 km/h. How much kinetic energy does it possess? K.E. =
1 answer:
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Answer:
a)
b)
Explanation:
a)
The width of the central bright in this diffraction pattern is given by:
when m is a natural number.
here:
- m is 1 (to find the central bright fringe)
- D is the distance from the slit to the screen
- a is the slit wide
- λ is the wavelength
So we have:
b)
Now, if we do m=2 we can find the distance to the second minima.
Now we need to subtract these distance, to get the width of the first bright fringe :
I hope it heps you!
Answer:
The magnitude of the frictional force between the car and the track is 367.763 N.
Explanation:
The roller coster has an initial gravitational potential energy, which is partially dissipated by friction and final gravitational potential energy is less. According to the Principle of Energy Conservation and Work-Energy Theorem, the motion of roller coster is represented by the following expression:
Where:
,
- Initial and final gravitational potential energy, measured in joules.
- Dissipated work due to friction, measured in joules.
Gravitational potential energy is described by the following formula:
Where:
- Mass, measured in kilograms.
- Gravitational constant, measured in meters per square second.
- Height with respect to reference point, measured in meters.
In addition, dissipated work due to friction is:
Where:
- Friction force, measured in newtons.
- Travelled distance, measured in meters.
Now, the energy equation is expanded and frictional force is cleared:
If ,
,
,
and
, then:
The magnitude of the frictional force between the car and the track is 367.763 N.