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Rzqust [24]
3 years ago
11

a rectilinear motion of a particle is defined by v3=x3. determine the velocity and acceleration at x=8m

Physics
1 answer:
Lyrx [107]3 years ago
7 0

Answer:

The velocity is 8 m/s and acceleration is 8 m/s^{2}

Explanation:

The motion of the particle is given by:

                                       v^{3}=x^{3\\}

                                  or, v= x .................................1

substitute x= 8m,

                                    v= 8 m/s

Now differentiate it with respect to time (t),

                         \frac{dv}{dt} = \frac{dx}{dt}

                   or,  \frac{dv}{dt} = v

                   ∴  \frac{dv}{dt} =  v

now substitute the value of v from equation 1,

                       \frac{dv}{dt} = x              

now at, x= 8

                        \frac{dv}{dt}  = 8

                     ∴ \frac{dv}{dt}  = 8 m/s^{2}

As

                        \frac{dv}{dt}  = acceleration

So the acceleration of the particle at x=8m is 8 m/s^{2} .

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3 years ago
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t = 2.35 s

Next, find the vertical displacement.  Given:

v₀ = 26 m/s sin 31.5° ≈ 13.6 m/s

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Find: Δy

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5 0
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