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Rzqust [24]
3 years ago
11

a rectilinear motion of a particle is defined by v3=x3. determine the velocity and acceleration at x=8m

Physics
1 answer:
Lyrx [107]3 years ago
7 0

Answer:

The velocity is 8 m/s and acceleration is 8 m/s^{2}

Explanation:

The motion of the particle is given by:

                                       v^{3}=x^{3\\}

                                  or, v= x .................................1

substitute x= 8m,

                                    v= 8 m/s

Now differentiate it with respect to time (t),

                         \frac{dv}{dt} = \frac{dx}{dt}

                   or,  \frac{dv}{dt} = v

                   ∴  \frac{dv}{dt} =  v

now substitute the value of v from equation 1,

                       \frac{dv}{dt} = x              

now at, x= 8

                        \frac{dv}{dt}  = 8

                     ∴ \frac{dv}{dt}  = 8 m/s^{2}

As

                        \frac{dv}{dt}  = acceleration

So the acceleration of the particle at x=8m is 8 m/s^{2} .

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3 years ago
You toss a rock up vertically at an initial speed of 39 feet per second and release it at an initial height of 6 feet. The rock
3241004551 [841]

Answer:

2.583 s, 29.77 ft and 1.219 s

Explanation:

Using equation of motion and taken the motion upward as positive, also a = g ( acceleration due to gravity) = - 32 fts⁻², V= 39 fts⁻¹ V₁ is final velocity, y is the distance in ft from the ground

H = 6 ft, the height from which it is tossed

V₁ = V + gt = V - gt

at maximum height the body came to rest momentarily V₁ = 0

0 = V - gt

-V = -gt

- 39 / -32 = t

t time to reach maximum height = 1.219 s

To Maximum height reached can be calculated with the formula

V₁² = V² + 2g( y - H) where H is the initial height reached by the tossed rock

where V₁ is the final velocity at maximum height which = 0

0 = V² - 2g(y-H) where y is the distance traveled from the ground

-V² = -2g(y-H)

₋V² / -2g = y-H

(V²/2g) + H = y in ft

(39² / (2 × 32)) + 6

y = 29.77 ft

The total time it will be in air can be calculated with the formula below

y = H + Vt - 0.5gt² from y-H = ut + 0.5at²

0.5gt² - Vt - H = 0 since the body returned to the ground ( y = 0)

0.5gt² - Vt - H = 0

using quadratic formula

- (-V)² ± √ ((-V²) - 4 × 0.5g × -H) / (2 × 0.5 × g)

(V ± √ (V² + 2gH)) ÷ g

substitute the values into the expression

t = (39 + √(39² + (2×-32× 6)))/ 32 or (39 - √ (39² + (2 × -32×6))/ 32

t = (39 + √(1521 +384))/32 = (39 + √1905) / 32  = 2.583 s

t = (39 - √1905) / 32 =  -0.15 s

The will remain in air (V ± √ (V² + 2gH)) / g seconds. It will reach a maximum height of (V²/2g) + H feet after V/g seconds

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3 years ago
What is the magnitude b of the magnetic field at the location of the charge due to the current-carrying wire?
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Answer:

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Explanation:

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Can a plane mirror produce a real image? Explain.
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4 0
3 years ago
A trumpet player, using her ear, hears 5 beats per second when she plays a note on her trumpet and simultaneously sounds a 440 H
german

<h2>Frequency of trumpet wire = 445 Hz</h2>

Explanation:

The given  frequency of tuning fork is 440 Hz . It produces 5 beats with trumpet wire . That means , the frequency of wire can be 440 ± 5

It can be either 445 or 435

Now the length of wire is increased , by which its frequency decreases . Because frequency is inversely proportional to length of wire .

If we decrease the frequency in 435 , the difference between tuning fork frequency and wire frequency will become greater than 5 even . So it cannot produce 3 beats with it .

If we decrease frequency from 445 , it can become 443 Hz . It gives 3 beat with the tuning fork as given .

Thus the initial frequency of wire is 445 Hz

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3 years ago
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