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3 years ago

Which of these events is associated with September 11, 2001?

1 answer:

7 0

Terrorist attacks on the United States is the answer.

On September 11, 2001 that was the day New York got attacked by terrorists. The Twin Towers were the ones that got affected, 2,996 people (maybe more) died during that attacked. The terrorists were one of the 2,996 people that died (19 of them died). more than 6,000 were injured that day.
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A two slit pattern is viewed on a screen 1.00m from the slits if the two third-order minima are 22.0 cm apart what is the width

Bingel [31]

Answer:

4.4 cm

Explanation:

Given:

Distance of the screen from the slit, D = 1 m

Distance between two third order interference minimas, x = 22 cm

Let's say, minima occurs at:

$x_n = (n + \frac{1}{2}) \frac{wL}{d}$

We have:

$2x_2 = 2(2 + \frac{1}{2}) * \frac{w*22}{d}$

Calculating further for the width of the central bright fringe, we have:

$\frac{w}{d} = \frac{22}{5}$

= 4.4 cm

Note: w in representswavelength

8 0

3 years ago

Describe two forms of energy-efficient transportation.

vodka [1.7K]

Electricity which may efficient transportation if you develop your way depending contact metal basis , such as electric train .

-Water is from of heat-energy using solar power which run a turbine may be wheel on a railway path.

6 0

3 years ago

How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57×10−21 n

hichkok12 [17]

Answer:

891 excess electrons must be present on each sphere

Explanation:

One Charge = q1 = q

Force = F = 4.57*10^-21 N

Other charge = q2 =q

Distance = r = 20 cm = 0.2 m

permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)

Using Coulomb's law,

F=[1/4pieo]q1q2/r^2

F = [1/4pieo]q^2 / r^2

q^2 =F [4pieo]r^2

q = r*sq rt F[4pieo]

q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]

q = 1.42614*10^ -16 C

number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19

n =891

891 excess electrons must be present on each sphere

5 0

3 years ago

Electromagnetic force is present when electromagnetic fields

AlekseyPX

b is the correct answer

4 0

3 years ago

Read 2 more answers

an airplane is moving with a constant velocity in level flight. compare the magnitude of the forward force by the engines to the

Iteru [2.4K]

The two forces are equal in magnitude

Explanation:

We can answer this question by applying Newton's second law of motion, which states that

$\sum F = ma$

where

$\sum F$ is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, the airplane is moving with constant velocity, so its acceleration is zero:

a = 0

This means that the equation becomes

$\sum F = 0$

There are two forces acting on the airplane in the horizontal direction:

- The forward force exerted by the engine, F

- The frictional drag force, D, backward

So the net force on the plane along the horizontal direction is

$\sum F = F-D$

However we also said that

$\sum F = 0$

Combining the two equations, we find

$F-D=0 \rightarrow F=D$

So, the two forces have same magnitude.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0

3 years ago