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Sav [38]
3 years ago
6

Consider the reversible reaction A ( g ) − ⇀ ↽ − B ( g ) Which K values would indicate that there is more B than A at equilibriu

m? K = 9 × 10 – 5 K = 0.4 K = 5000 K = 8 × 10 7
Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer:

5000 and 8\times 10^{7} indicate that there is more B than A at equilibrium

Explanation:

For the given reaction: K=\frac{[B]}{[A]}

where [B] and [A] represents equilibrium concentration B and A respectively. K represents equilibrium constant

More B than A at equilibrium means, [B] > [A]

So, K=\frac{[B]}{[A]}>1

As, both 5000 and 8\times 10^{7} are greater than 1 therefore these two K values indicate that there is more B than A at equilibrium

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Answer:

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2 years ago
In an isothermal gas chromatography experiment using an ECD detector, 1.69 nmols of nchlorohexane, C6H13Cl, was added as an inte
prohojiy [21]

Answer:

The amount of Chlorodecane in the unknown is 0.105nmols

Explanation:

a) Since the GC is in an isothermal state, Chlorohexane C6H13Cl (1.69 nmols) because of its lower boiling point will elute first and Chlorodecane C12H21Cl will elute second.

The area of the first peak corresponding to Chlorohexane is 32434 units.

The area of the second peak corresponding to chlorodecane is 2022 units.

Since the response factor of the compound is not given in question and considering the response factor is same for both the compounds, the answer will be as follow:

1.69 nmols of Chlorohexane gives 32434 units

How much of chlorodecane gives 2022 units

By cross multiplication;

Moles of Chlorodecane = 2022*1.69/32434

                                         =0.105nmols

4 0
3 years ago
How much heat, in calories, is given off when 1.25 grams of silver is cooled from 100.0 degrees Celsius to 80 degrees Celsius? (
lapo4ka [179]
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Can two organisms belong to the same family but different classes? Explain.
slega [8]
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kari74 [83]

The half-life in years of Neptunium-237 which was the first isotope is 2.1 10^{6} years.

Neptunium is most stable and Neptunium-237 is undergoes alpha decay, it means Neptunium-237 is decays by the emission of alpha particles . Seven alpha particles is emitted during decay of  Neptunium-237.  Neptunium-237 is radioactive actinide  elements and first  transuranium element.

The transuranium synthesis process involves creating a transuranium element through the transmutation process . The transmutation process  is the process of creating heavy elements from light elements. Hence the process is the transmutation of light elements. There are two types: artificial and natural transmutation.

to learn more about transuranium element.

brainly.com/question/1491386

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