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kaheart [24]
3 years ago
14

At a certain temperature and pressure, 0.20 mol of carbon dioxide has a volume of 3.1 L. A 3.1-L sample of hydrogen at the same

temperature and pressure ____.
Chemistry
1 answer:
Misha Larkins [42]3 years ago
4 0
Answer:
            <span>A 3.1 L sample of hydrogen at the same temperature and pressure contains the same number of molecules.

Explanation:
                   As we know ;"1 mole of any gas at STP occupies exactly 22.4 L of volume". Therefore, CO</span>₂ and H₂ gas having same number of moles (0.20 moles) will occupy exactly the same volume.

Now, converting moles into number of molecules,

# of Molecules  =  Moles × 6.022 × 10²³

Putting value of mole,

# of Molecules  =  0.2 mol × 6.022 × 10²³ molecules.mol⁻¹

# of Molecules  =  1.20 × 10²³ molecules

Hence, both gases will contain 1.20 × 10²³ molecules.
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A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

\frac{V}{T}=const.

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where in this problem we have:

V_1=490 mL is the initial volume of the gas

T_1=-35.0^{\circ} + 273 = 238 K is the initial temperature

T_2=42.0^{\circ}+273=315 K is the final temperature

Solving for V2, we find the final volume of the gas:

V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL

8 0
4 years ago
Draw the curved arrow mechanism for the conversion of aniline into benzenediazonium ion, and draw the final product that forms a
kogti [31]
Below Mechanism shows the mechanism of formation of diazonium ion. Aniline is treated with Nitrosonium ion which is generated in situ by the reaction of Sodium nitrile and strong acid. The resulting <span>benzenediazonium ion on reaction with CuBr yields Bromobenzene and on treatment with CuCN gives Benzonitrile. Mechanism is as folow,</span>

3 0
3 years ago
A chemical reaction produces 138 mol of HBr gas. What volume will that gas occupy at STP?
stepan [7]

Answer:

The second one

Explanation:

5 0
3 years ago
Read 2 more answers
What is the ph of a solution labeled .30 trimethylamine k for trimethylamine is 7.42 x 10^4
valentina_108 [34]

Answer:the pH is 12

Explanation:

First We need to understand the structure of trimethylamine

Due to the grades of the bond in the nitrogen with a hybridization sp3 is 108° approximately, then is generated a dipole magnetic at the upper side of the nitrogen, this dipole magnetic going to attract a hydrogen molecule of the water making the water more alkaline

C3H9N+ H2O --> C3H9NH + OH-

k=\frac{[C3H9NH]*[OH-]}{[C3H9N]}

Then:

The concentration of the trimethylamine is 0.3 and the concentration of the ion C3H9NH is equal to the OH- relying on the stoichiometric equation. We could find the concentration of the OH- ion with the square root of the multiplication between k and the concentration of trimethylamine

[OH-]=\sqrt{ 0.3*7.42x10^{-4}}

[OH-]=0.01

pH=14-(-log[OH-])

pH=12

5 0
3 years ago
If you could help me that would be awesome
elixir [45]
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8 0
3 years ago
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