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kaheart [24]
4 years ago
14

At a certain temperature and pressure, 0.20 mol of carbon dioxide has a volume of 3.1 L. A 3.1-L sample of hydrogen at the same

temperature and pressure ____.
Chemistry
1 answer:
Misha Larkins [42]4 years ago
4 0
Answer:
            <span>A 3.1 L sample of hydrogen at the same temperature and pressure contains the same number of molecules.

Explanation:
                   As we know ;"1 mole of any gas at STP occupies exactly 22.4 L of volume". Therefore, CO</span>₂ and H₂ gas having same number of moles (0.20 moles) will occupy exactly the same volume.

Now, converting moles into number of molecules,

# of Molecules  =  Moles × 6.022 × 10²³

Putting value of mole,

# of Molecules  =  0.2 mol × 6.022 × 10²³ molecules.mol⁻¹

# of Molecules  =  1.20 × 10²³ molecules

Hence, both gases will contain 1.20 × 10²³ molecules.
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Be sure to answer all parts. Write the equations representing the following processes. In each case, be sure to indicate the phy
barxatty [35]

Answer:

1.S^{-}(g)+e^{-} \rightarrow S^{2-}(g)

2.Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}

3.The electron affinity of  Mg^{2+} is zero.

4.O^{2-}(g) \rightarrow O^{-}(g)+e^{-}

Explanation:

1.

<u>Electron affinity:</u>

It is defined as the amount of energy change when an electron is added to atom in the gaseous phase.

The electron affinity of S^{-} is as follows.

S^{-}(g)+e^{-} \rightarrow S^{2-}(g)

2.

<u>Ionization energy</u>:

Amount of energy required to removal of an electron from an isolated gaseous atom.

The third ionization energy of Titanium is as follows.

Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}

3.

The electronic configuration of Mg: 1s^{2}2s^{2}2p^{6}3s^{2}

By the removal of two electrons from a magnesium element we get Mg^{2+} ion.

Mg^{2+} has inert gas configuration i.e,1s^{2}2s^{2}2p^{6}

Hence, it does not require more electrons to get stability.

Therefore,the electron affinity of  Mg^{2+} is zero.

4.

The ionization energy of O^{2-} is follows.

O^{2-}(g) \rightarrow O^{-}(g)+e^{-}

3 0
3 years ago
what is a major drawback of using fossil fuels they warmn the planet they contain no greenohuse gases
Charra [1.4K]

The major drawback of fossil fuels is that they warm the planet i.e. they cause global warming.

The reaction typically gives off heat and light as well. The general equation for a complete combustion reaction is:

                                  Fuel + O2 → CO2 + H2O + ENERGY

<h3>Disadvantages of Fossil fuels</h3>

The term "fossil fuels" refers to flammable organic geologic formations, including dead organic matter that has been buried hundreds of feet beneath sediment.

  • Fossil fuel emissions include various oxides, such as carbon, nitrogen, and sulfate, which cause acid rain and harm the soil's fertility and water quality.
  • Both coal and petroleum burning discharge a significant amount of pollutants into the atmosphere, contributing to pollution levels.
  • Gases like carbon dioxide are released through the burning of fossil fuels, which aids in climate change.

To view similar questions on Fossil fuels, refer to:

brainly.com/question/14339391

#SPJ4

7 0
1 year ago
Fluorine-21 has a half life of approximately 5 seconds. You have 340 grams, what fraction of the original nuclei would remain af
madreJ [45]
The half life equation is -->P(t) = Pi (0.5) ^ (t/c)
c is equal to the element to reach its half-life (5 seconds)t is equal to the duration of time the element is expose to (20 seconds)Pi is the initial amount (340)0.5 is the base of this exponential function to represent half-life.P(t) is the expression for the function of time

P(20) = 340 (0.5)^20/5P(20) = 340 (0.5) ^4P(20)= 21.25 grams
Fraction = P(t)/Pi              = P(20)/Pi              =21.25/340              =1/16
Therefore, when given 20 seconds, 340 grams of Fluorine-21 will degrade to 21.25 grams OR 1/16 of its original mass.
Hope this method helps! (This is my answer btw, I think you may have accidentally posted twice?)
7 0
3 years ago
An electrochemical cell has the following standard cell notation.
icang [17]

The cell notation is:

Mg(s)|Mg^{+2}(aq)||Ag^{+}(aq)|Ag(s)

here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell

in anodic half cell : oxidation takes place [loss of electrons]

in cathodic half cell: reduction takes place [gain of electrons]

1) this is a galvanic cell

2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode

E^{0}_{Mg}=-2.38V

E^{0}_{Ag}=+0.80V

Therefore

E^{0}_{cell}=0.80-(-2.38)=+3.18V

3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative

ΔG^{0}=-nFE^{0}

As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.

7 0
3 years ago
Students have been given a choice of four elements: Lithium, Magnesium, Sulfur, and Bromine. Which two metallic atoms and one no
Afina-wow [57]

Answer:magnesium and sulfur Mg2S

Explanation:

6 0
3 years ago
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