Question

A 730 kg Mini runs into a stationary 2500 kg SUV. If the Mini was moving at 10. M , how s fast will it be moving after making a completely inelastic collision with the SUV?

Answer 1

Answer:

2.26m/s

Explanation:

Since it is an inelastic collision, the mini and the Suv move together after the collision. The law of conservation of momentum states that the total momentum before and after the collision is conserved:

Using law of conservation of momentum,

$m_{1} u_{1}+m_{2} u_{2}=\left(m_{1}+m_{2}\right) v$

Given that,

$m_{1}$= 730 kg

$u_{1}$ = 10 m/s

$u_{2}$ = 0

$m_2 =$2500kg

v = ?

When substituting the given values in the above equation, we get

$730(10) + 2500(0) = (730+2500)v\\\\7300 + 0 = 3230v\\\\v = \frac{7300}{3200} \\\\= 2.26m/s$