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Step2247 [10]
3 years ago
5

Explain the process of synaptic transmission, beginning with the neurotransmitters at the axon terminal of the presynaptic cell

and ending with the impulse being sent down the postsynaptic cell.
Physics
2 answers:
nydimaria [60]3 years ago
8 0

The synapse is actually the link between 2 neurons. Now when an action potential contacts the synaptic knob of a neuron, the voltage-gate calcium channels are unlocked, resulting in an influx of positively charged calcium ions into the cell. This makes the vesicles containing neurotransmitters, for example acetylcholine, to travel towards the pre-synaptic membrane. When the vesicle arrives at the membrane, the contents are released into the synaptic cleft by exocytosis. Neurotransmitters disperse across the space, down to its concentration gradient, up until it reaches the post-synaptic membrane, where it connects to the correct neuroreceptors. Connecting to the neuroreceptors results in depolarisation in the post-syanaptic neuron as voltage-gated sodium channels are also opened, and the positively charged sodium ions travel into the cell. When adequate neurotransmitters bind to neuroreceptors, the post-synaptic membrane overcame the threshold level of depolarisation and an action potential is made and the impulse is transmitted.

skelet666 [1.2K]3 years ago
5 0

Answer:

Synaptic transmission, beginning with the neurotransmitters at the axon terminal of the presynaptic cell and ending with the impulse being sent down to the postsynaptic cell isn't very complicated as it sounds. When an action potential contacts the synaptic knob of a neuron, the voltagegate calcium channels are unlocked, resulting in an influx of positively charged calcium ions into the cell. So, that makes the vesicles containing neurotransmitters to travel towards the presynaptic membrane. Then when the vesicle arrives at the membrane, the contents are released into the synaptic cleft by exocytosis. Neurotransmitters disperse across the space, down to its concentration gradient, up until it reaches the postsynaptic membrane, where it connects to the correct neuro receptors. Connecting to the neuro receptors results in depolarization in the post synaptic neuron as voltagegated sodium channels are also opened, and the positively charged sodium ions travel into the cell. When adequate neurotransmitters bind to neuroreceptors, the postsynaptic membrane overcame the threshold level of depolarisation and an action potential is made and the impulse is transmitted.

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ziro4ka [17]
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Since initial velocity is zero hence , u = 0

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d = 0.5 \times 9.8 \times {4.2}^{2}
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4 years ago
Arysha enjoys playing lacrosse on the school team. Suppose Arysha throws a lacrosse ball with a force of 6 N, and the resulting
olasank [31]

Answer:

Mass = 0.14kg

Explanation:

Given

Force = 6N

Acceleration = 43m/s^2

Required

Determine the mass of the ball

This question will be answered using Newton's second law of motion.

Which states that

Force = Mass * Acceleration

Substitute values for Force and Acceleration

6N = Mass * 43m/s^2

Make Mass the subject

Mass = \frac{6N}{43m/s^2}

Mass = 0.13953488372

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3 0
3 years ago
A car has a mass of 850 kg. By pushing on the car, Evan increases its speed
Dmitry_Shevchenko [17]

Answer:

I=1,2•10³ kg•m/s

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4 years ago
Read 2 more answers
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baherus [9]

Answer:

823.46 kgm/s

Explanation:

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So, mgh = 1/2mv²

From here, his velocity just as he reaches the surface of the water is

v = √2gh

h = 9 m and g = 9.8 m/s²

v = √(2 × 9 × 9.8) m/s

v = √176.4 m/s

v₁ = 13.28 m/s

So his velocity just as he reaches the surface of the water is 13.28 m/s.

Now he dives into 32 cm = 0.32 m of water and stops so his final velocity v₂ = 0.

So, if we take the upward direction as positive, his initial momentum at the surface of the water is p₁ = -mv₁. His final momentum is p₂ = mv₂.

His momentum change or impulse, J = p₂ - p₁ = mv₂ - (-mv₁) = mv₂ + mv₁. Since m = Henri LaMothe's mass = 62 kg,

J = (62 × 0 + 62 × 13.28) kgm/s = 0 +  823.46 kgm/s = 823.46 kgm/s

So the magnitude of the impulse J of the water on him is 823.46 kgm/s

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Answer:

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