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3 years ago

A pendulum on plant X is 0.25 meters long and the period is 4 seconds. What is “g” on Planet X?

Physics

1 answer:

Monica [59]3 years ago

7 0

Answer:

The value of g = 0.6168 m/s².

Explanation:

Given that,

On a planet X,

Length of the pendulum(L) = 0.25 meters,

Time period of the pendulum(T) = 4 seconds.

We have to find the 'g' value on the planet.

The 'g' value on a planet can be found by a pendulum with help of the formula,

T = 2π × $\frac{\sqrt{L} }{\sqrt{g} }$

From this, g = 4π² × $\frac{L}{T^{2} }$

Using the above formula and substituting the values,we get,

g = 0.6168 m/s².

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A force of 450 N moves a body through 300 cm in the direction of force. Calculate the work

OlgaM077 [116]

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150J

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3 years ago

A disk-shaped merry-go-round of radius 2.63 m and mass 152 kg rotates freely with an angular speed of 0.526 rev/s. A 51.7 kg per

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Explanation:

Given

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$\omega =3.30 rad/s$

mass disc $M=152 kg$

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velocity of Person $v=2.76 m/s$

moment of inertia $I=Mr^2$

$I=0.5\times 152\times 2.63^2=827.64 kg-m^2$

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$L_i=I\omega +mvr$

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$L_i=2731.212+375.27=3106.48 Js$

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$I_f=0.5Mr^2+mr^2$

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final angular momentum

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Conserving angular momentum

$L_i=L_f$

$3106.48=1408.97\times \omega _f$

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3 years ago