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bixtya [17]
3 years ago
13

A pendulum on plant X is 0.25 meters long and the period is 4 seconds. What is “g” on Planet X?

Physics
1 answer:
Monica [59]3 years ago
7 0

Answer:

The value of g = 0.6168 m/s².

Explanation:

Given that,

On a planet X,

Length of the pendulum(L) = 0.25 meters,

Time period of the pendulum(T) = 4 seconds.

We have to find the 'g' value on the planet.

The 'g' value on a planet can be found by a pendulum with help of the formula,

T = 2π × \frac{\sqrt{L} }{\sqrt{g} }

From this,  g = 4π² × \frac{L}{T^{2} }

Using the above formula and substituting the values,we get,

g = 0.6168 m/s².

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New pressure of the gas increases by 26.5% with respect to initial pressure, new volume decreases 27% with respect to initial volume and new temperature decreases 8% with respect to initial volume.

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If we assume the gas is a perfect gas we can use the perfect gas equation:

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\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}(1)

Where subscripts 1 shows before the isothermal process and 2 after it, because isothermal means constant temperature T1=T2, and pressure increases by 10% means P2=1,1*P1, using these facts on (1) we have:

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  • For Isobaric process:

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Where subscripts 2 shows before the isobaric process and 3 after it, because isobaric means constant pressure P2=P3, and volume decreases by 20% means V3=0.8*V2, using these facts on (3) we have:

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  • For Isochoric process:

\frac{P_{3}V_{3}}{T_{3}}=\frac{P_{4}V_{4}}{T_{4}} (5)

Where subscripts 3 shows before the isochoric process and 4 after it, because isochoric means constant volume V3=V4, and temperature increases by 15% means T4=1.15*T3, using these facts on (5) we have:

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So now because P4=1.15*P3, P2=P3 and P2=1.1*P1:

P_{4}=1.15*1.1P_{1}=1.265P1

This is, the new pressure of the gas increases by 26.5%  with respect to initial pressure.

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V_{4}=\frac{0.8}{1.1}V_{1}=0.72V1

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T4=1,15*T3, T3=0.8*T2 and T1=T2:

T_{4}=1.15*0.8T_{1}=0.92T1

The new temperature decreases 8% with respect to initial volume.

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