A pendulum on plant X is 0.25 meters long and the period is 4 seconds. What is “g” on Planet X?
1 answer:
Answer:
The value of g = 0.6168 m/s².
Explanation:
Given that,
On a planet X,
Length of the pendulum(L) = 0.25 meters,
Time period of the pendulum(T) = 4 seconds.
We have to find the 'g' value on the planet.
The 'g' value on a planet can be found by a pendulum with help of the formula,
T = 2π ×
From this, g = 4π² ×
Using the above formula and substituting the values,we get,
g = 0.6168 m/s².
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Answer:
E = 1.04*10⁻¹ N/C
Explanation:
Assuming no other forces acting on the proton than the electric field, as this is uniform, we can calculate the acceleration of the proton, with the following kinematic equation:
As the proton is coming at rest after travelling 0.200 m to the right, vf = 0, and x = 0.200 m.
Replacing this values in the equation above, we can solve for a, as follows:
According to Newton´s 2nd Law, and applying the definition of an electric field, we can say the following:
F = mp*a = q*E
For a proton, we have the following values:
mp = 1.67*10⁻²⁷ kg
q = e = 1.6*10⁻¹⁹ C
So, we can solve for E (in magnitude) , as follows:
⇒ E = 1.04*10⁻¹ N/C