Answer:
-5/2 because there is -5y/2 but we have to take coefficient only so -5/2
Evidence are simply facts to support a claim, while counterexamples are instances to show the contradictions in a claim
<em>The question is incomplete, as the required drop-down menus are missing. So, I will give a general explanation</em>
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To show that a statement is true, you need evidence.
Take for instance:
The evidence that the above proof is true is by taking the <em>squares of both sides of </em>
However, a counterexample does not need a proof per se.
What a counterexample needs is just an instance or example, to show that:
An instance to prove that: is false is:
Hence, the complete statement could be:
<em>In a direct proof, evidence is used to support a proof
. On the other hand, a counterexample is a single example that shows that a proof is false.</em>
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Read more about evidence and counterexample at:
brainly.com/question/88496
Step-by-step explanation:
The equivalent expression of 8x + 12 - x = 7x + 12
Answer:
No, mn is not even if m and n are odd.
If m and n are odd, then mn is odd as well.
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Proof:
If m is odd, then it is in the form m = 2p+1, where p is some integer.
So if p = 0, then m = 1. If p = 1, then m = 3, and so on.
Similarly, if n is odd then n = 2q+1 for some integer q.
Multiply out m and n using the distribution rule
m*n = (2p+1)*(2q+1)
m*n = 2p(2q+1) + 1(2q+1)
m*n = 4pq+2p+2q+1
m*n = 2( 2pq+p+q) + 1
m*n = 2r + 1
note how I replaced the "2pq+p+q" portion with r. So I let r = 2pq+p+q, which is an integer.
The result 2r+1 is some other odd number as it fits the form 2*(integer)+1
Therefore, multiplying any two odd numbers will result in some other odd number.
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Examples:
- 3*5 = 15
- 7*9 = 63
- 11*15 = 165
- 9*3 = 27
So there is no way to have m*n be even if both m and n are odd.
The general rules are as follows
- odd * odd = odd
- even * odd = even
- even * even = even
The proof of the other two cases would follow a similar line of reasoning as shown above.
