Can someone pls help me with this problem
2 answers:
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Answer:
Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.
Step-by-step explanation:
Given that,
A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.
From Pythagorean Theorem,
(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+
Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.
∴y²= x²+10²
Differentiating with respect to t
Since the car driving towards the intersection at 13 m/s.
so,
Now
= -12 m/s
Negative sign denotes the distance between the car and the person decrease.
Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.
The triangle pay $32 more for that day than it paid per day during the first period of time.
Step-by-step explanation:
The given is,
Triangle Construction pays Square Insurance $5,980
To insure a construction site for 92 days
To extend the insurance beyond the 92 days costs $97 per day
Triangle extends the insurance by 1 day
Step:1
Insurance per day from the 92 days period,
Where, Total insurance for 92 days = $ 5,980
Period = 92 days
From the values, equation becomes,
= $ 65 per day
Step:2
Insurance per day after the 92 days,
= $ 97
Amount Pay for that day than it paid per day during the first period of time,
= $32
Result:
The triangle pay $32 more for that day than it paid per day during the first period of time, if the Triangle Construction pays Square Insurance $5,980 to insure a construction site for 92 days and to extend the insurance beyond the 92 days costs $97 per day.
we know,
so,
now,