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motikmotik
3 years ago
6

Sjwjdbehdhenwhdbrjxbejsnejfbejdnfbrjrnd

Chemistry
2 answers:
Mrrafil [7]3 years ago
7 0
Wow. Great question.
Keith_Richards [23]3 years ago
6 0

Answegood

Explanation:this answer is two it has letters

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What did the Bohr model assume about the motion of electrons?
Makovka662 [10]

Answer:

A

Explanation:

THAT'S THE ANSWER EYEUSKSBAW

8 0
3 years ago
A type of steel made from copper-alloyed steel that protects itself from corrosion is _______________ steel.
never [62]
Weathering steel or another name for it is cortensteel.
3 0
3 years ago
The chemical equation below shows the formation of aluminum oxide (Al2O3) from aluminum (Al) and oxygen (O2).
Rufina [12.5K]

Answer:

Mass = 182.4 g

Explanation:

Given data:

Number of moles of Al₂O₃ = 3.80 mol

Mass of oxygen required = ?

Solution:

Chemical equation:

4Al + 3O₂    →       2Al₂O₃

Now we will compare the moles of aluminum oxide and oxygen.

                Al₂O₃           :           O₂

                   2               :            3

                 3.80            :         3/2×3.80 = 5.7

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 5.7 mol × 32 g/mol

Mass = 182.4 g

4 0
3 years ago
Urea is an organic compound widely used as a fertilizer. Its solubility in water allows it to be made into aqueous fertilizer so
skad [1K]

Answer:

3 hydrogen bonds.

Explanation:

This is because the urea molecule has an oxygen atom bound with double bonds to the central carbon atom, and this oxygen can form a hydrogen bond with water, as well as both terminal amine groups that can also form a hydrogen bond each because of the lone pair of electrons on the nitrogen group.

6 0
3 years ago
Calculate the number of hydrogen atoms in a sample of hydrazine . Be sure your answer has a unit symbol if necessary, and round
gladu [14]

Answer:

atoms \ H= 9.767x10^{24}atoms

Explanation:

Hello!

In this case, considering that the mass of hydrazine is missing, we can assume it is 130.0 g (a problem found on ethernet). In such a way, since we need a mass-mole-atoms relationship by which we can compute moles of hydrazine given its molar mass (32.06 g/mol), then the moles of hydrogen considering one mole of hydrazine has four moles of hydrogen and one mole of hydrogen has 6.022x10²³ atoms (Avogadro's number); therefore, we proceed as shown below:

atoms \ H=130.0gN_2H_4*\frac{1molN_2H_4}{32.06gN_2H_4} *\frac{4molH}{1molN_2H_4} *\frac{6.022x10^{23}atoms}{1molH}\\\\atoms \ H= 9.767x10^{24}atoms

Notice 130.0 g has four significant figures, therefore the result is displayed with four as well.

Best regards!

7 0
3 years ago
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