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3 years ago

I got the correct answer, but I don't know why. Could someone explain this to me?

Chemistry

1 answer:

MakcuM [25]3 years ago

3 0

Answer:-

Option 2

Explanation:-

In a multi step reaction, the overall reaction is as fast as the slowest step only.

So the rate of a multistep reaction is the same as the rate of its slowest step.

The gas phase reaction was found to be second order wrt NO2.

So the slowest step must have 2 NO2 since the dependence is second order on NO2.

It was also found to be zero order wrt CO.

So the slowest step must not contain any CO since it’s presence has no effect on the reaction (zero order).

Among all options, only number 2 meets the two criterion

Thus the steps are

NO2 + NO2 – NO3 + NO (Slow)

NO3 + CO – NO2 + CO2 (Fast)

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2 years ago

Which of the following is NOT true regarding Rutherford's Gold Foil experiment?

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Answer:

The area around the nucleus must be of low mass.

Explanation:

Rutherford`s experiment showed that there are some positive charges in the center of the atoms, and because they are all together, they will give a great mass to the atom.

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3 years ago

A mixture containing 20 mole % butane, 35 mole % pentane and rest

notka56 [123]

Answer:

2.5 % butane, 42.2 % pentane and 55.3 % hexane

Explanation:

Hello,

In this case, the mass balance for each substance is given by:

$Butane:z_bF=y_bD+x_bB\\\\Pentane: z_pF=y_pD+x_pB\\\\Hexane: z_hF=y_hD+x_hB$

Whereas $y$ accounts for the fractions at the outlet distillate and $x$ for the fractions at the outlet bottoms. Moreover, with the 90 % recovery of butane, we can write:

$0.9=\frac{y_bD}{z_bF}$

So we can compute the product of the molar fraction of butane at the distillate by total distillate flow by assuming a 100-mol feed:

$y_bD=0.9*z_bF=0.9*0.2*100mol=18mol$

The total distillate flow:

$y_bD=18mol\\\\D=\frac{18mol}{0.95} =18.95mol$

And the total bottoms flow:

$F=D+B\\\\B=F-D=100mol-18.95mol=81.05mol$

Next, by using the mass balance of butane, we compute the molar fraction of butane at the bottoms:

$x_b=\frac{z_bF-y_bD}{B} =\frac{0.2*100mol-18mol}{81.05} =0.025$

Then, the molar fraction of pentane and hexane:

$x_p=\frac{z_pF-y_pD}{B} =\frac{0.35*100mol-0.04*18.95mol}{81.05} =0.422$

$x_h=\frac{z_hF-y_hD}{B} =\frac{(1-0.2-0.35)*100mol-(1-0.95-0.04)*18.95mol}{81.05} =0.553$

Therefore, the molar composition of the bottom product is 2.5 % butane, 42.2 % pentane and 55.3 % hexane.

NOTE: notice the result is independent of the value of the assumed feed, it means that no matter the basis, the compositions will be the same for the same recovery of butane at the feed, only the flows will change.

Regards.

8 0

3 years ago

Read 2 more answers

Arrange the following elements in order of decreasing ionization energy: Cl, Si, P, Ar *

Elden [556K]

Answer:

Ar > Cl > P > Si.

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