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3 years ago

Which of the following describes boundaries?

Engineering

1 answer:

torisob [31]3 years ago

7 0

Answer:

The correct option is;

(2) Boundaries are primarily used to indicate which functions a product will perform as opposed to the functions a user will perform

Explanation:

Product specifications accompanying most products, specifies the product boundaries and limitations which are to be acceptable to (or meet the requirement of) the intended user

The intended user has the option to then set boundaries of use of the product within his possession.

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Calculate the potential energy in kJ of a human body (70 kg) possesses on top of the Empire State Building (1,250 ft tall).

Dvinal [7]

Answer:

Potential energy = 261.633 kJ

Explanation:

The potential energy is the energy stored in an object due to its position above Earth's surface.

The potential energy formula is :

$E_{p} =m.g.h$

Where $E_{p}$ is the potential energy

m is the object mass

g is the gravity

and h is the height referred to a comparison plane

We start by converting the height in feets to meters

$h=1250ft=1250ft.\frac{0.3048m}{1ft} =381m\\h=381m$

$m=70kg$

and

$g=9.81\frac{m}{s^{2} }$

$E_{p} =(70kg).(9.81\frac{m}{s^{2} } )(381m)=261632.7 kg.\frac{m}{s^{2} } .m$

Where

$kg.\frac{m}{s^{2} } =N$

N is Newton

$N.m=J$

J is Joule. Joule is the energy unit

$E_{p} =261632.7 J$

We divide it by 1000 to obtain kJ

$261632.7 \frac{J}{1000} =261.633 kJ$

4 0

3 years ago

Two common types of glue

dolphi86 [110]

Answer:

white craft glue

yellow wood glue

Explanation:

the answer is this!

was it correct?sir!?

8 0

2 years ago

Read 2 more answers

Consider a car manufacturing firm, with more than 100 facilities worldwide. What would be the positive aspects of having high nu

liberstina [14]

More work getting done and faster

7 0

3 years ago

Read 2 more answers

Please view the file attached below and help me answer all the questions!!

evablogger [386]

Answe whats the question i can help you

Explanation:

8 0

3 years ago

The beam is supported by a pin at A and a roller at B which has negligible weight and a radius of 15 mm. If the coefficient of s

Anettt [7]

Answer:

33.4

Explanation:

Step 1:

\sumMo=0 (moment about the origin)

Fb(15)-Fc(15)=0

Fb=Fc

Step 2:

\sumFx=0

-Fb-Fccos\theta+Ncsin\theta=0

Fc=0.3Nc=Fb

-0.3Nc-0.3Nccos\theta+Ncsin\theta=0

(-0.3-cos\theta+sin\theta)Nc=0----(1)

\sumFy=0

Nccos\theta+Fcsin\theta-Nb=0

Nccos\theta+0.3Ncsin\theta-Nc=0

Nc[cos\theta+0.3sin\theta-1]=0--------(2)

Solving eq (1) and eq (2)

\theta=33.4

Step 3:

As the roller is a two force member

2(90-\phi)+\theta=180

\phi=\theta/2

\phi=Tan(\muN/N)-1

\phi=16.7

\theta=2x16.7=33.4

5 0

3 years ago