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My name is Ann [436]
2 years ago
10

An elevator starts from rest with a constant. upward acceleration andmoves 1m in the first. 1.8 s. A passenger in the elevator i

s holding a. 8.7 kg bundle at the end of a vertical cord.. What is the tension in the cord as the ele-. vator accelerates? The acceleration of gravity. is 9.8 m/s2 .. Answer in units of N
Physics
1 answer:
mina [271]2 years ago
5 0
Newton's second law tells you: 

Sum of forces on an object = ma 

Here, the forces acting on the bundle are the tension in the string and the force of gravity, these two must combine to yield the acceleration of the bundle. 

So we have: 

T-mg = ma 

or T=m(g+a) 

We know m=8.7kg, we need to find a from the information 

starting from rest, an accelerating object covers distance according to: 

<span>dist = 1/2 at^2 </span>

to cover 1m in 1.8s, we have: 

a=2d/t^2 = 2x1/1.8^2 = 0.62 m/s/s 

Thus, the tension in the string is: 

<span>T = m(g+a)
=  8.7</span>kg(9.8m/s/s+0.62m/s/s) 
<span>
<span>T =  90.654 N
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
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We can solve the problem by requiring the equilibrium of the forces and the equilibrium of torques.

1) Equilibrium of forces:
T_1 - W_p - W_s + T_2 =0
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W_s = (200kg)(9.81 m/s^2)=1962 N is the weight of the scaffold
Re-arranging, we can write the equation as
T_1 = 2845 N-T_2 (1)

2) Equilibrium of torques:
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Using W_p = 883 N and replacing T1 with (1), we find
2845 N \cdot 3 m - T_2 \cdot 3 m - 833 N \cdot 2 m - T_2 \cdot 3 m=0
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