1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
My name is Ann [436]
2 years ago
10

An elevator starts from rest with a constant. upward acceleration andmoves 1m in the first. 1.8 s. A passenger in the elevator i

s holding a. 8.7 kg bundle at the end of a vertical cord.. What is the tension in the cord as the ele-. vator accelerates? The acceleration of gravity. is 9.8 m/s2 .. Answer in units of N
Physics
1 answer:
mina [271]2 years ago
5 0
Newton's second law tells you: 

Sum of forces on an object = ma 

Here, the forces acting on the bundle are the tension in the string and the force of gravity, these two must combine to yield the acceleration of the bundle. 

So we have: 

T-mg = ma 

or T=m(g+a) 

We know m=8.7kg, we need to find a from the information 

starting from rest, an accelerating object covers distance according to: 

<span>dist = 1/2 at^2 </span>

to cover 1m in 1.8s, we have: 

a=2d/t^2 = 2x1/1.8^2 = 0.62 m/s/s 

Thus, the tension in the string is: 

<span>T = m(g+a)
=  8.7</span>kg(9.8m/s/s+0.62m/s/s) 
<span>
<span>T =  90.654 N
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
You might be interested in
A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotr
mart [117]

Answer:

diameter of largest orbit is 0.60 m

Explanation:

given data

isotopes accelerates KE = 6.5 MeV

magnetic field B = 1.2 T

to find out

diameter

solution

first we find velocity from kinetic energy equation

KE = 1/2 × m×v²   ........1

6.5 × 1.6 × 10^{-19} = 1/2 × 1.672 × 10^{-27} ×v²

v = 3.5 × 10^{7} m/s

so

radius will be

radius = \frac{m*v}{B*q}   ........2

radius =  \frac{1.672*10^{-27}*3.5*10^{7}}{1.2*1.6*10^{-19}}  

radius = 0.30

so diameter = 2 × 0.30

so diameter of largest orbit is 0.60 m

8 0
3 years ago
Read 2 more answers
Erica is working in the lab. She wants to remove the fine dust particles suspended in a sample of oil. Which method is she most
mash [69]
Option a is right answer that is reverse osmosis.
5 0
3 years ago
Read 2 more answers
Which fundamental force has a small range and is always an attractive force?
erica [24]

Answer:

gravitational force is a fundamental force and also , it does have a small range and is always an attractive force.

Explanation:

5 0
3 years ago
What cells in the nervous signals travel through the nervous system
kirill115 [55]

Answer:Although the nervous system is very complex, nervous tissue consists of just two basic types of nerve cells: neurons and glial cells Neurons are the structural and functional units of the nervous system They transmit electrical signals, called nerve impulses. Glial cells provide support for neurons.

Explanation:

3 0
3 years ago
Read 2 more answers
A velocity selector has a magnetic field of magnitude 0.22 T perpendicular to an electric field of magnitude 0.51 MV/m.
ohaa [14]

Answer:

speed of a particle  = 2.31 × 10^{6} m/s

energy of proton required = 27.77 KeV

energy of electron required =  15.171 eV

Explanation:

given data

magnetic field of magnitude = 0.22 T

electric field of magnitude = 0.51 MV/m

to find out

speed of a particle and energy must protons have to pass through undeflected and  energy must electrons have to pass through undeflected

solution

we know that force due to magnetic and electric field is express as

force due to magnetic field B = qvB    ..............1

and force due to electric field E = qE   .....................2

so without deflection force due to magnetic field  = force due to electric field  

so here qvB = qE

and V = \frac{E}{B}    ...................3

put here value

V =  \frac{0.51*10^6}{0.22}

speed of a particle  = 2.31 × 10^{6} m/s

and

now energy of proton required will be here as

energy of proton required = mass of proton × \frac{V^2}{2}

put here value

energy of proton required = 1.67 × 10^{-27} × \frac{(2.31*10^6)^2}{2}

energy of proton required = 4.45 × 10^{-15} J

energy of proton required = 4.45 × 10^{-15} J ÷ (1.602 × 10^{-19}

energy of proton required = 27777.777 eV

energy of proton required = 27.77 KeV

and

now we get here energy of electron required that is

energy of electron required = mass of electron × \frac{V^2}{2}

put here value

energy of electron required = 9.11 × 10^{-31} × \frac{(2.31*10^6)^2}{2}

energy of electron required =  24.305× 10^{-19} J

energy of electron required =  24.305 × 10^{-19} J ÷ (1.602 × 10^{-19}  

energy of electron required =  15.171 eV

5 0
3 years ago
Read 2 more answers
Other questions:
  • An experiment is designed to test what color of light will activate a photoelectric cell the best. The photocell is set in a cir
    10·2 answers
  • Is it possible for a baseball to have as large a momentum as a much more massive bowling ball
    13·1 answer
  • Image that Grade 7 students are looking at a spherical ornament that has mirror-like surface. The students exclaim how strange t
    6·1 answer
  • What is proposed as evidence that supports the Big Bang Theory?
    15·2 answers
  • A trip is taken that passes through the following points in order
    13·1 answer
  • NEED HELP PLEASE 15 POINTS PLEASEE NEED HELP
    13·2 answers
  • A storm front moves in and Rachel and Pam notice the column of mercury in the barometer rises only to 736 mm. Assume the density
    11·1 answer
  • Your best friend has very low energy levels and complains of not being able to sleep at night. Determine the BMI score that woul
    6·1 answer
  • A car travels eastwards at 60km/h for 2h, then travels northwards at 20km/h for 8h. Find,
    13·1 answer
  • How many cm3 are there in 1 dm3?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!