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olga55 [171]
2 years ago
7

Carbon atoms can be identified based on the # of which subatomic particles

Chemistry
1 answer:
34kurt2 years ago
6 0

Answer: protons and neutrons.

The nucleus is made up of 3 subatomic particles that are protons,neutrons and electrons.  

General notation of an element is _{Z}^{A}\textrm{X}

where, X is the Element, A is the Atomic Mass and Z is the Atomic Number

If we know the number of protons we can easily find out the atomic number of any element because Atomic Number = Number of protons in an element.

And in addition if we know the number of neutrons we can easily find out the atomic mass of an element because

Atomic Mass = (Number of protons) + (Number of neutrons)

If we get to know the atomic number and atomic mass, we can easily tell what element is it by looking from the periodic table.

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Please balance the equation, putting the correct coefficient in each box.
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Answer: Bi(OH)_3+3HNO_3\rightarrow 3H_2O+Bi(NO_3)_3

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced equation will be:

Bi(OH)_3+3HNO_3\rightarrow 3H_2O+Bi(NO_3)_3

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Discovered electrons have fixed amounts of energy and orbit the nucleus similar to planets? A. John dalton B. J.J. Thomson C. Er
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2 years ago
Read 2 more answers
Given the following data:
bagirrra123 [75]

176.0 \; \text{kJ} \cdot \text{mol}^{-1}

As long as the equation in question can be expressed as the sum of the three equations with known enthalpy change, its \Delta H can be determined with the Hess's Law. The key is to find the appropriate coefficient for each of the given equations.

Let the three equations with \Delta H given be denoted as (1), (2), (3), and the last equation (4). Let a, b, and c be letters such that a \times (1) + b \times (2) + c \times (3) = (4). This relationship shall hold for all chemicals involved.

There are three unknowns; it would thus take at least three equations to find their values. Species present on both sides of the equation would cancel out. Thus, let coefficients on the reactant side be positive and those on the product side be negative, such that duplicates would cancel out arithmetically. For instance, 3 + (-1) = 2 shall resemble the number of \text{H}_2 left on the product side when the second equation is directly added to the third. Similarly

  • \text{NH}_4 \text{Cl} \; (s): -2 \; a = 1
  • \text{NH}_3\; (g): -2 \; b = -1
  • \text{HCl} \; (g): 2 \; c = -1

Thus

a = -1/2\\b = 1/2\\c = -1/2 and

-\frac{1}{2} \times (1) + \frac{1}{2} \times (2) - \frac{1}{2} \times (3)= (4)

Verify this conclusion against a fourth species involved- \text{N}_2 \; (g) for instance. Nitrogen isn't present in the net equation. The sum of its coefficient shall, therefore, be zero.

a + b = -1/2 + 1/2 = 0

Apply the Hess's Law based on the coefficients to find the enthalpy change of the last equation.

\Delta H _{(4)} = -\frac{1}{2} \; \Delta H _{(1)} + \frac{1}{2} \; \Delta H _{(2)} - \frac{1}{2} \; \Delta H _{(3)}\\\phantom{\Delta H _{(4)}} = -\frac{1}{2} \times (-628.9)+ \frac{1}{2} \times (-92.2) - \frac{1}{2} \times (184.7) \\\phantom{\Delta H _{(4)}} = 176.0 \; \text{kJ} \cdot \text{mol}^{-1}

3 0
3 years ago
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