32.17 grams of oxygen.
Don't know why you're asking. It looks like you've already answered the question yourself.
You have 10.47 grams of benzene. Dividing by its molar mass of 78.1074 means that you have 10.47/78.1074 = 0.134046 moles of benzene. Looking at the reaction, for every 2 moles of benzene, you need 15 moles of O2. So 0.134046 / 2 * 15 = 1.005346 moles of O2 is needed to consume all the benzene. And then multiply by O2's molar mass and you get 1.005346 * 32 = 32.17109 which when rounded to the nearest hundredth, gives you 32.17 grams.
Answer:
Throughout the overview section following portion, the description and according to particular circumstance is defined.
Explanation:
As per the question,
⇒ 
- A weak basis seems to be NH3. It serves as a base since the aqueous solution or phase is protonated. But NH3 +, just becoming a weak base, is therefore deprotonated into form NH3, and therefore also 90% of ammonia becomes found throughout NH3 state in aqueous solution.
⇒ 
However, it is also available in NH3 form throughout the aqueous solution much of the moment.
It is matter. Hope this helps.
Im no sure what it is i just love helping little boys out. at this age it gives me a thrill.
Answer:
C. overlapping p orbitals.
Explanation:
It is a covalent bond formed between neighbouring atom's unbonded p orbitals,
