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Vilka [71]
3 years ago
9

Why is dilute, not concentrated, hydrochloric acid used during preparation of cyclohexaanol?

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
3 0
I think <span>500 m but i just think i dont know </span>
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What happens to the energy added during a phase change?
Ivanshal [37]

Answer:You're answer is D: it is converted to kinetic energy

Explanation:

During a change of phase, the average kinetic energy of the molecules stays the same, but the average potential energy changes. ... My interpretation is that during a phase change, the temperature remains equal, but the kinetic energy of its particles increase/decrease.

                                             LINK:

https://chemistry.stackexchange.com/questions/82163/clarification-of-kinetic-energy-during-phase-change

7 0
4 years ago
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1.For the reaction P4 O10(s) + 6H2O(l) → 4H3PO4(aq), what mass of P
Alex17521 [72]
P₄O₁₀ + 6H₂O → 4H₃PO₄
The equation shows us that the molar ratio of
P₄O₁₀ : 6H₂O = 1:6

We also know that one mole of a substance contains 6.02 x 10²³ particles. We can use this to calculate the moles of water.
moles(H₂O) = (5.51 x 10²³) / (6.02 x 10²³)
= 0.92 mole
That means moles of P₄O₁₀ = 0.92 / 6
= 0.15

Each mole of P₄O₁₀ contains 4 moles of P. 
moles(P) = 4 x 0.15 = 0.6 mol
Mr of P = 207 grams per mol
Mass of P = 207 x 0.6
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5 0
3 years ago
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Can anyone can answer practice problem exercise 6.5
NemiM [27]

Answer: Add more information please! Thanks!

Explanation:

6 0
3 years ago
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If you are told that one of them is Cr2O3 and the other is OsO4, which one do you expect to be the yellow solid?
Katen [24]
From own experience, I know that OsO4 is colorless, but Cr2O3 is actually a solid green from what I have seen. but I guess it could appear yellow-greenish.
7 0
4 years ago
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The energy required to split apart dichlorine according to the equation is 3.99 × 10-19 J/molecule. Cl2(g) → 2Cl(g) Calculate th
Natasha2012 [34]

Answer:

The frequency of the photon that can dissociate dichlorine is 6.02×10¹⁴ Hz

Explanation:

The energy of a photon is given by the equation:

E=h·f

E=3.99×10⁻¹⁹ J/molecule

h (Planck's constant)=6.626×10⁻³⁴ m²·kg/s

∴ f=E/h

f=\frac{3.99*10^{-19}J}{6.626*10^{-34} m²·kg/s}=6.02×10¹⁴ s⁻¹= 6.02×10¹⁴ Hz

5 0
3 years ago
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