Answer:
2.652 g/h.
Explanation:
Burn rate (in mg/min) = 44.2 mg/min
Burn rate (in m/h) =?
We'll begin by converting 44.2 mg/min to g/min. This can be obtained as follow:
1 mg/min = 0.001 g/min
Therefore,
44.2 mg/min = 44.2 mg/min × 0.001 g/min / 1 mg/min
44.2 mg/min = 0.0442 g/min
Finally, we shall convert 0.0442 g/min to g/h. This can be obtained as follow:
1 g/min = 60 g/h
Therefore,
0.0442 g/min = 0.0442 g/min × 60 g/h / 1 g/min
0.0442 g/min = 2.652 g/h
Therefore, 44.2 mg/min is equivalent to 2.652 g/h.
Thus, the burn rate (in m/h) is 2.652 g/h.
-The products and reactants of both reactions are gases. -A catalyst is used for reaction 2. What do the symbols tell you about the conditions of the reaction shown to the right? ... They show that the number of atoms of each element is the same in the products and reactants.
<span>Heat capacity is the ratio of the amount of heat energy transferred to an object to the resulting increase in its temperature. Molar heat capacity is a ..... Data collected during a constant-pressure calorimetry experiment can be used to calculate the heat capacity of an unknown substance</span>
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-When Ksp is the solubility product constant for a solid substance when it
dissolved in an aqueous solution, and measure the level at which a solute
dissolves in the solution.
- and we have the solubility and it is the maximum quantity of solute which can dissolve in a certain solute
we can assume the solubility = X = 2.2 x 10^-5 M
and when the balanced reaction equation is:
Mn(OH)2(s) ↔ Mn2+ + 2OH-
∴ the Ksp expression is = [Mn2+] [OH-]^2
when [Mn2+] = X = 2.2 x 10^-5 M
and [OH-] = 2X = 2*(2.2 x 10^-5) = 4.4 x 10^-5 M
by substitution:
∴ Ksp = X * (2X)^2
= (2.2 x 10^-5)(4.4 x 10^-5)^2
= 4.3 x 10^-14