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Pie
2 years ago
8

Where did you put H an He? What are your reasoning for placement?

Chemistry
1 answer:
aksik [14]2 years ago
3 0

Answer:

On the placement of hydrogen and helium in the periodic system

H1=1

He2=2

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What is a sensory neuron?
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Answer: Nerve cells within the nervous system that are in charge of converting external stimuli from the organism's environment into internal electrical impulses.

4 0
3 years ago
What is the most likely charge on an ion formed by an element with a valence electron configuration of ns2np4
Andreas93 [3]

Answer:

2-

Explanation:

For an element to be stable, it must follow the octet rule: an atom will gain, lose or share electrons until its valence shell is complete with 8 electrons.

An element with the valence electron configuration ns²np⁴ has 6 (2+4) electrons in its valence shell. Thus, in order to fulfill the octet, it will gain 2 electrons. As a consequence, it will form an anion with charge 2-.

6 0
3 years ago
Under which conditions will sugar most likely dissolve fastest in a cup of water?
zheka24 [161]
If the cup of water contained hot water. Sugar will dissolve a lot slower if it was in room temperature and even slower if it was in cold water.
3 0
2 years ago
1‑propanol ( n ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure a
Alex777 [14]

Answer:

y_{prop} = 0.134; y_{iso} = 0.866

The partial pressure of isopropanol = 34.04 Torr; The partial pressure of propanol = 5.26 Torr

Explanation:

For each of the solutions:

mole fraction of isopropanol  (x_{iso}) = 1 - mole fraction of propanol (x_{prop}).

Given: mole fraction of propanol = 0.247. Thus, the mole fraction of isopropanol = 1 - 0.247 = 0.753.

Furthermole, the partial pressure of isopropanol = x_{iso}*vapor pressure of isopropanol = 0.753*45.2 Torr = 34.04 Torr

The partial pressure of propanol = x_{prop}*vapor pressure of propanol = 0.247*20.9 Torr = 5.16 Torr

Similarly,

In the vapor phase,

The mole fraction of propanol (y_{prop}) = \frac{P_{prop} }{P_{prop}+P_{iso}}

Where, P_{prop} is the partial pressure of propanol and P_{iso} is the partial pressure of isopropanol.

Therefore,

y_{prop} = 5.26/(34.04+5.16) = 0.134

y_{iso} = 1 - 0.134 = 0.866

5 0
3 years ago
Round off the measurement to three significant figures 12.17º C
prohojiy [21]
12.2 C
It has 3 significant figures now.
6 0
3 years ago
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