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Aleksandr [31]
3 years ago
11

A person on a rocket traveling at 0.47 c (with respect to the Earth) observes a meteor come from behind and pass her at a speed

she measures as0.47 c.
How fast is the meteor moving with respect to the Earth?
Physics
1 answer:
zhannawk [14.2K]3 years ago
7 0

The concept to solve this problem is related to the relativistic physics for which the speed of the object in different frames of reference is related. This concept is called Velocity-addition formula

and can be written as,

u = \frac{v+u'}{1+\frac{vu'}{c^2}}

Where,

u = Velocity of a body within a Lorentz Frame

v = Velocity of a second frame

u'= The transformed velocity of the body within the second frame

c = speed of light

Replacing we have to

u = \frac{v+u'}{1+\frac{vu'}{c^2}}

u = \frac{0.47c+0.47c}{1+\frac{0.47c*0.47c}{c^2}}

u = 0.769c

u \approx 230'700.000m/s

Therefore the meteor moving with respect to the Earth to 230'700.000m/s

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ASAP pls answer right if can’t see picture don’t answer
Anna35 [415]

Answer:

Not sure but

F = m* a

32= 5 * a

a= 6.4 m/s^2

6 0
3 years ago
It took a crew 9 h 36 min to row 8 km upstream and back again. If the rate of flow of the stream was 2 km/h, what was the rowing
babunello [35]

Answer:

3 km/h

Explanation:

Let's call the rowing speed in still water x, in km/h.

Rowing speed in upstream is: x - 2 km/h

Rowing speed in downstream is: x + 2 km/h

It took a crew 9 h 36 min ( = 9 3/5 = 48/5) to row 8 km upstream and back again. Therefore:

8/(x - 2) + 8/(x + 2) = 48/5      (notice that: time = distance/speed)

Multiplying by x² - 2², which is equivalent to (x-2)*(x+2)

8*(x+2) + 8*(x-2) =  (48/5)*(x² - 4)

Dividing  by 8

(x+2) + (x-2) = (6/5)*(x² - 4)

2*x = (6/5)*x² - 24/5

0 =  (6/5)*x² - 2*x - 24/5

Using quadratic formula

x = \frac{2 \pm \sqrt{(-2)^2 - 4(6/5)(-24/5)}}{2(6/5)}

x = \frac{2 \pm 5.2}{2.4}

x_1 = \frac{2 + 5.2}{2.4}

x_1 = 3

x_2 = \frac{2 - 5.2}{2.4}

x_2 = -1\; 1/3

A negative result has no sense, therefore the rowing speed in still water was 3 km/h

7 0
3 years ago
Radar is used to determine distances to various objects by measuring the round-trip time for an echo from the object. (a) How fa
BartSMP [9]

Answer

given,

Echo time = t = 1000 s

speed = ?

v = \dfrac{d}{t}

a) speed of electromagnetic wave

c = \dfrac{d}{t}

wave travels Venus two time

c = \dfrac{2d}{t}

d = \dfrac{ct}{2}

d = \dfrac{3 \times 10^8\times 1000}{2}

d = 1.5 x 10¹¹ m

b) now, echo time

    c = \dfrac{2d}{t}

    t = \dfrac{2d}{c}

    t = \dfrac{2\times 75}{3 \times 10^8}

          t = 5 x 10⁻⁷ s

8 0
3 years ago
Air resistance is a nonconservative force. It always opposes the motion of an object. An airplane flies from New York to Atlanta
Lorico [155]

Answer:

is always negative

Explanation:

Air resistance is a non-conservative force it opposes the motion of an object.It is a force that is always directed opposite to the displacement.

6 0
4 years ago
Read 2 more answers
The longer the time between the arrival of the P-wave and S-wave, the _______ is the epicenter.
Brrunno [24]

The longer the time between the arrival of the P-wave and S-wave, the <u>farther away</u> is the epicenter.

<h3>What is epicenter and the relation between P-wave and S-wave?</h3>
  • The point on the earth's surface vertically above the hypocenter (or focus), point in the crust where a seismic rupture begins is said to be epicenter.
  • There are two types of waves during earthquakes, they are:
  1. P - wave
  2. S - wave
  • Each seismograph records the times when the first (P waves) and second (S waves) seismic waves arrive.
  • From the graph, through the information, scientists can determine how fast the waves are traveling.
  • The longer the time between the arrival of the P-wave and S-wave, the farther away is the epicenter.

Hence, Option B is the correct answer.

Learn more about epicenter,

brainly.com/question/28136716

#SPJ1

7 0
2 years ago
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