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katrin [286]
3 years ago
11

Your spaceship has just crashed on the moon. You were scheduled to rendezvous with a mother ship 200 miles away on the lighted s

urface of the moon, but the rough landing has ruined your ship and destroyed all the equipment on board except for the 15 items listed below. Your crew’s survival depends on reaching the mother ship, so you must choose the most critical items available for the 200-mile trip. Your task is to rank the 15 items in terms of their importance for survival. Place a number 1 by the most important item, number 2 by the second most important, and so on, through number 15, the least important.
Box of matches
Magnetic compass
Solar-powered heater
One case dehydrated milk
Two 45 caliber pistols
Signal flares
Self-inflating life raft
Parachute silk
First aid kit
50' of rope
Solar-powered receiver-transmitter
Food concentrate
Stellar map
Five gallons of water
Two 100 lb. tanks of Oxygen
Physics
1 answer:
Svetach [21]3 years ago
8 0

Answer:

1} Two 100 lb. tanks of Oxygen

2) Five gallons of water

3) Food concentrate

4) One case dehydrated milk

5) Solar-powered heater

6) Solar-powered receiver-transmitter

7} First aid kit

8) Box of matches

9) Stellar map

10) Magnetic compass

11) Two 45 caliber pistols

12) Signal flares

13) 50' of rope

14) Self-inflating life raft

15) Parachute silk

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MakcuM [25]

Answer:

210

Explanation:

A ball rolls horizontally off the cliff at a speed of 30 m/s. It takes 7 seconds for the ball to hit the ground. What is the height of the cliff and the horizontal distance traveled by the ball?

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Will give brainliest
NNADVOKAT [17]

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3 years ago
A ball is thrown vertically upwards with an initial velocity of 20.00 m/s. Neglecting air resistance, how long is the ball in th
algol [13]

Answer:

1) The greatest height attained by the ball equals 20.387 meters.

2) The time it takes for the ball to reach 15 meters approximately equals 1 second.

Explanation:

The greatest height will be attained when the ball stop's in the air and starts falling back to the earth.

thus using third equation of kinematics we obtain the height attained as

v^2=u^2+2as

where

'v' is the final speed of the ball

'u' is the initial speed of the ball

'a' is the acceleration that the ball is under which in this case equals 9.81 m/s^{2}

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Thus for maximum height applying the values in the equation we get

0=20^{2}-2\times 9.81\times h\\\\\therefore h=\frac{20^{2}}{2\times 9.81}=20.387meters

Using the same equation we can find the speed of the ball when it reaches 15 meters of height as  

v^2=20^{2}-2\times 9.81\times 15\\\\v^{2}=105.7\\\\\therefore v=10.28m/s

the time it takes to reduce the velocity to this value can be found by first equation of kinematics as

v=u+at\\\\t=\frac{v-u}{a}\\\\t=\frac{10.28-20}{-9.81}=0.991seconds\approx 1second

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