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katrin [286]
3 years ago
11

Your spaceship has just crashed on the moon. You were scheduled to rendezvous with a mother ship 200 miles away on the lighted s

urface of the moon, but the rough landing has ruined your ship and destroyed all the equipment on board except for the 15 items listed below. Your crew’s survival depends on reaching the mother ship, so you must choose the most critical items available for the 200-mile trip. Your task is to rank the 15 items in terms of their importance for survival. Place a number 1 by the most important item, number 2 by the second most important, and so on, through number 15, the least important.
Box of matches
Magnetic compass
Solar-powered heater
One case dehydrated milk
Two 45 caliber pistols
Signal flares
Self-inflating life raft
Parachute silk
First aid kit
50' of rope
Solar-powered receiver-transmitter
Food concentrate
Stellar map
Five gallons of water
Two 100 lb. tanks of Oxygen
Physics
1 answer:
Svetach [21]3 years ago
8 0

Answer:

1} Two 100 lb. tanks of Oxygen

2) Five gallons of water

3) Food concentrate

4) One case dehydrated milk

5) Solar-powered heater

6) Solar-powered receiver-transmitter

7} First aid kit

8) Box of matches

9) Stellar map

10) Magnetic compass

11) Two 45 caliber pistols

12) Signal flares

13) 50' of rope

14) Self-inflating life raft

15) Parachute silk

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Answer:

a) In a parallel plate capacitor the capacitance is

C = \frac{Q}{V} = \epsilon_0\frac{A}{d}

So, in order to halve the capacitance the plate separation should be twice the original distance.

b) Same question as (a).

c) According to the above equations, the charge stored in a capacitor is directly proportional to the plate separation.

\frac{Q}{V} = \frac{A}{d}

In order to halve the charge stored the plate separation should be half the original distance.

d) Same question as (c).

e) The energy stored in a capacitor is

U = \frac{1}{2}CV^2 = \frac{1}{2}\epsilon_0\frac{A}{d}(Ed)^2 = \frac{1}{2}\epsilon_0AE^2d

In order to halve the energy stored in the capacitor, the plate separation should be twice the original distance.

f) Same question as (e).

g) The energy density is given by the following equation

u = \frac{\frac{1}{2}CV^2}{Ad} = \frac{\frac{1}{2}\epsilon_0\frac{A}{d}(E^2d^2)}{Ad} = \frac{1}{2}\epsilon_0E^2.

As it turns out, the energy density is independent from the geometric factors. This makes sense, because the electric field in a parallel field capacitor is independent from the distance.

3 0
3 years ago
In our lab experiment on Ohm's law, the power supply is connected to a circuit containing one resistor, and a direct current of
lapo4ka [179]

Answer: (A) 3.0=A

Explanation: In order to explain this problem we have to use the OHM law, given by: V=R*I

Besides, we have to consider the resitance equivalent for a parallel connection. This is given by:

1/Re=1/R1+1/R2

If we connect the same resistance, the equivalent resistance is R/2.

Initlally  the current is 1.5 A when one resistance is connected to the batttery. When a second resistance with the same value is connected in parallel to the battery, we have V=Re*Ifinal= (R/2)*Ifinal

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A tow truck drags a stalled car along a road. The chain makes an angle of 30° with the road and the tension in the chain is 1400
AURORKA [14]

Answer:

The work is done by the truck pulling the car 1 km is 1,212,436 J

Explanation:

Work is defined as the force that is applied on a body to move it from one point to another. When a force is applied, an energy transfer occurs. Then it can be said that work is energy in motion.

So work is one of the forms of energy transmission between bodies. To perform a job, you must exert a force on a body and it moves.

In the International System of Units, work is measured in Joule. A Joule is the work that a constant force of 1 Newton does on a body that moves 1 meter in the same direction and direction as the force. Then, Joule is equivalent to Newton per meter.

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves:

Work= Force*Distante* cos (θ)

In this case:

  • Force= 1,400 N= 1,400 kg*\frac{m}{s^{2} }
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  • θ= Angle that exists between the direction of the force and the direction= 30°

Replacing:

Work= 1,400 N* 1,000 m* cos (30°)

Work= 1,212,435. 565 Joule≅ 1,212,436 J

<u><em> The work is done by the truck pulling the car 1 km is 1,212,436 J</em></u>

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