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Vsevolod [243]
3 years ago
8

Eric throws a basketball straight up into the air. As it rises, which form of energy is increasing? A. elastic potential energy

B. electrical energy C. gravitational potential energy D. kinetic energy
Physics
2 answers:
Art [367]3 years ago
7 0
I think it's kinetic energy
exis [7]3 years ago
5 0

Answer:

C) Gravitational potential energy

Explanation:

As ball is thrown upwards then we can say that speed of the ball will decrease as it will move upwards.

This is due to gravity which act opposite to the motion of the ball

So as the ball is thrown upwards the initial kinetic energy of the ball will start decreasing as it will move upwards

Here we also know that gravitational potential energy of the ball is given as

U = mgh

so as the ball start rising upwards the potential energy of the ball will increase

so here correct answer will be

C) Gravitational potential energy

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3 years ago
The briquette is better fuel than wood why give two reason​
Mekhanik [1.2K]

Answer:

wood

Explanation:

you can last longer with wood because you are using up gas when you drive your car that will mean that you will have to go and find gas if you run out an example like we are in the zombie apocalypse.

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2 years ago
An open system starts with 52 J of mechanical energy. The energy changes
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Answer:

I think the answer is D,54 joules

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3 years ago
The sound intensity from a jack hammer breaking concrete is 2.0W/m2 at a distance of 2.0 m from the point of impact. This is suf
kupik [55]

Answer:

(a) I_{1}=3.2*10^{-3}W/m^{2}

(b) \beta =95dB

Explanation:

Given data

Distance r₁=50 m

Distance r₂=2 m

Intensity I₂=2.0 W/m²

To find

(a) The Sound Intensity I₁

(b) The Sound Intensity level β

Solution

For (a) the Sound Intensity I₁

\frac{I_{1} }{I_{2}}=\frac{(r_{2})^{2}  }{(r_{1})^{2} }\\I_{1} =I_{2}(\frac{(r_{2})^{2}  }{(r_{1})^{2} })\\I_{1}=(2.0W/m^{2} )(\frac{(2m)^{2}  }{(50m)^{2} })\\I_{1}=3.2*10^{-3}W/m^{2}

For (b) the Sound Intensity level β

The Sound Intensity level β is calculated as follow

\beta =(10dB)log_{10}(\frac{I}{I_{o} } )\\\beta  =(10dB)log_{10}(\frac{3.2*10^{-3}W/m^{2}  }{1.0*10^{-12} W/m^{2} } )\\\beta =95dB

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3 years ago
Venn diagrams are used for comparing and contrasting topics. The overlapping sections show characteristics that the topics have
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Carry energy and follow a pattern

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