Answer:
0.05 cm
Explanation:
The compression of the original spring = 12 - 8.55 cm = 3.45 cm = 0.0345 m
By Hooke's law, F = ke
Where F is the applied force, k is the spring constant and e is the extension or compression. In the question, F is the weight of the car.
k = F/e = 1355 × 9.8 / 0.0345 = 384898.55 N/m
This is the spring constant of the original spring. The question mentions that the force constant of the new spring is 5855.00 N/m smaller. Hence, the force constant of the new spring is 384898.55 - 5855 = 379043.55 N/m
With the new spring installed, the compression will be
e = F/k = 1355 × 9.8 / 379043.55 = 0.035 m = 3.5 cm
The difference in the compressions of both springs = 3.5 cm - 3.45 cm = 0.05 cm
Answer:
One arm row: Latissmus Dorsi (Lat)
Dumbell flys: Shoulders
Machine back press: pectorals
Push downs: Triceps
Explanation:
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Answer:
Distance-how far smthing travels.
Explanation:
That is correct what you did
Answer:
The electromotive force (e) or e.m.f. is the energy provided by a cell or battery per coulomb of charge passing through it, it is measured in volts (V).
Answer:
<u><em>Frictional force refers to the force generated by two surfaces that contacts and slide against each other.</em></u>
~Hope this helps~ T^T