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exis [7]
3 years ago
12

How many moles of sulfur are needed to produce 15.0 mol of sulfur dioxide?

Chemistry
2 answers:
Brut [27]3 years ago
4 0
<span>S + O2 =  SO2

1 mole S ------------- 1 mole SO2
( moles S ) --------- 15.0 moles SO2

moles S = 15.0 x 1 / 1

moles S = 15.0 / 1

= 15.0 moles S</span>
LUCKY_DIMON [66]3 years ago
4 0

Answer : The number of moles of sulfur needed are, 15 moles

Explanation : Given,

Moles of sulfur dioxide = 15 mole

The balanced chemical reaction will be,

S+O_2\rightarrow SO_2

By the stoichiometry we can say that, 1 mole of sulfur react with 1 mole of oxygen gas to give 1 mole of sulfur dioxide as a product.

From the balanced chemical reaction we conclude that,

As, 1 mole of sulfur dioxide produces from 1 mole of sulfur

So, 15 moles of sulfur dioxide produces from 15 moles of sulfur

Therefore, the number of moles of sulfur needed are, 15 moles

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Which of the following sets of quantum numbers is NOT allowed? a. n = 5, l= 4, ml= –2, ms = +1/2 b. n = 2, l = 1, ml= 0, ms = +1
klemol [59]

Answer:

C

Explanation:

the n value must always be greater than the l value

8 0
3 years ago
Two isotopes of lithium are found in nature Li6 has a mass of 6. 02u and Li7 has a mass of 7.02u . Use the atomic weight of lith
alexandr402 [8]

The isotope that is more abundant, given the data is isotope Li7

<h3>Assumption</h3>
  • Let Li6 be isotope A
  • Let Li7 be isotope B

<h3>How to determine whiche isotope is more abundant</h3>
  • Molar mass of isotope A (Li6) = 6.02 u
  • Molar mass of isotope B (Li7) = 7.02 u
  • Atomic mass of lithium = 6.94 u
  • Abundance of A = A%
  • Abundance of B = (100 - A)%

Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]

6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]

6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]

6.94 = [6.02A% + 702 - 7.02A%] / 100

Cross multiply

6.02A% + 702 - 7.02A% = 6.94 × 100

6.02A% + 702 - 7.02A% = 694

Collect like terms

6.02A% - 7.02A% = 694 - 702

-A% = -8

A% = 8%

Thus,

Abundance of B = (100 - A)%

Abundance of B = (100 - 8)%

Abundance of B = 92%

SUMMARY

  • Abundance of A (Li6) = 8%
  • Abundance of B (Li7) = 92%

From the above, isotope Li7 is more abundant.

Learn more about isotope:

brainly.com/question/24311846

#SPJ1

4 0
2 years ago
During which stage of life is a human most dependent on others?
AfilCa [17]

Erm, I think when they are little. When they are just born.

7 0
3 years ago
Read 2 more answers
Balance the following reaction.<br> A.) 4<br> B.) 2<br> C.) 5<br> D.) blank<br> E.) 3
slega [8]

Answer:

C.5

Hope this helps

7 0
3 years ago
Which of these conjugate acid-base pairs will not function as a buffer?
miv72 [106K]

Answer:HNO₃ and NO³⁻ would not function as buffer

Explanation:

The buffer solution are usually prepared by using  any  weak acid (which would partially dissociate)  and mixing this weak acid with its own conjugate base or any weak base (which would partially dissociate) and mixing with  with its conjugate acid.

A buffer solution is a solution which resists change in pH of the solution.

Since nitric acid is a very strong acid and hence neither nitric acid HNO₃ or its conjugate base NO³⁻ anionb is suitable for the preparation of buffer solution.

HCO³⁻ is a weak  acid and hence it can form a buffer solution with its conjugate base CO₃²-. so they can be used to form buffer.

C₂H₅COOH is a weak acid and hence it can also form buffer solution with its conjugate base.

So only HNO₃and NO³⁻ would not be able to form buffer

So option a is the answer.

8 0
3 years ago
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