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Ksju [112]
3 years ago
12

Which of the following metals will react with water to produce a metal hydroxide and hydrogen gas?

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
7 0
Na is the answer hope it help
You might be interested in
3. Give one example of an element and one
zhenek [66]

Answer:

Element: H (hydrogen)

Compound: H2O (water)

Explanation: An element is made up of a singular atom while a compound is made up of 2 or more

7 0
3 years ago
A 49.48-mL sample of an ammonia solution is analyzed by titration with HCl. It took 38.73 mL of 0.0952 M HCl to titrate the ammo
Kryger [21]

Answer:

M₂ = 0.0745 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = 0.0952 M

V₁ = 38.73 mL

M₂ = ?

V₂ = 49.48 mL

Using the above formula , the molarity of ammonia , can be calculated as ,

M₁V₁ = M₂V₂  

0.0952 M * 38.73 mL = M₂* 49.48 mL

M₂ = 0.0745 M

8 0
3 years ago
HELP ASAP!!!! PLEASE AND THANK YOU!!!! Aluminum, which has a specific heat capacity of 0.902 J/g◦C and a mass of 20.9 g absorbs
rosijanka [135]

Answer:

81.54 °C

Explanation:

Use the equation

q = mcΔT

348 = 20.9(0.902)(100-t)

t = 81.54 °C

*note, you don't have to convert these to kelvin since the difference will be the same

5 0
3 years ago
For some hypothetical metal, the equilibrium number of vacancies at 600°C is 1 × 1025 m-3. If the density and atomic weight of t
makvit [3.9K]

Answer:

\frac{N_{v}}{N}=1.92*10^{-4}

Explanation:

First of all we need to find the amount of atoms per volume (m³). We can do this using the density and the molar mass.

7.40 \frac{g}{cm^{3}}*\frac{1mol}{85.5 g}*\frac{6.023*10^{23}atoms}{1mol}*\frac{1000000 cm^{3}}{1m^{3}}=5.21*10^{28}\frac{atoms}{m^{3}}

Now, the fraction of vacancies is equal to the N(v)/N ratio.

  • N(v) is the number of vacancies 1*10^{25}m^{-3}
  • N is the number of atoms per volume calculated above.

Therefore:  

The fraction of vacancies at 600 °C will be:

\frac{N_{v}}{N}=\frac{1*10^{25}}{5.21*10^{28}}  

\frac{N_{v}}{N}=1.92*10^{-4}

I hope it helps you!

 

7 0
3 years ago
2.1 x 10^-3 x 2 x 10^2 =
Bumek [7]

Answer:

I believe it is B

Explanation:

hope it helps. please let me know if it's wrong

4 0
2 years ago
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