Answer:
Oxidized and reducing agent: manganese.
Reduced and oxidizing agent: mercury.
Explanation:
Hello!
In this case, for the reaction:

We keep in mind that the species that increase the oxidation state is the oxidized one whereas the one that decrease the oxidation state is the reduced one; therefore manganese is the oxidized one as well as the reducing agent because it goes from 0 to +2 and mercury the reduced one as well as the oxidizing agent because it goes from 2+ to 0.
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Answer:

Explanation:
The density formula is mass over volume.

Rearrange the formula for the mass, m. Multiply both sides of the formula by v.


Mass can be found by multiplying the density and volume. The density is 0.65 grams per milliliter and the volume is 45.0 cubic centimeters.
- A cubic centimeter is equal to a milliliter.
- Therefore, 45 cubic centimeters also equals 45 milliliters.

Substitute the values into the formula.

Multiply. Note the milliliters, or mL will cancel out.


The mass of the wood is 29.25 grams.
Answer:-
and
radiation.
Explanations:- Alpha particle is helium nucleus with two protons and two neutrons and so it has +2 charge where as gamma is a form of light, so these are rays and not particles. Since these are rays, the charges for gamma rays is zero means they are neutral.
When alpha particles are passed through electromagnetic field they are repelled by the positive plate and attracted by the negative plate as there is an attraction between opposite charges. So, the line we see towards positive plat is representing an alpha particle radiation.
Since gamma rays are neutral, they are not deflected in electromagnetic field and go straight. So, the other line in the diagram is representing gamma rays radiation.
Answer:
The answer to your question is ΔE = 0.752 kJ/mol
Explanation:
Data
mass of sample = 0.125 g
Heat capacity = 5.1 x 10² J/°C
ΔT = 11.8°C
ΔE = ?
Formula
ΔE = ΔQ + w
We suppose that work W = 0
ΔQ = mCΔT, then
ΔE = mCΔT
Substitution
ΔE = (0.125)(5.1 x 10²)(11.8)
Simplification
ΔE = (63.75)(11.8)
Result
ΔE = 752.25 J/mol or ΔE = 0.752 kJ/mol