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avanturin [10]
3 years ago
14

Classify each amino acid by the chemical properties of its side chain (R group) at pH 7·Select the amino acid that fits best in

each category. Each amino acid will be used only once. 1. This amino acid has a positively charged R group: Select answer 2. This amino acid has a negatively charged R group! Select answer 3. This amino acid has a neutral polar R group: Sect answer 4 This amino acid has a nonpolar aliphatic R tryptophan aspartate valine arginine Select answer 5. This amino acid has an aromatic R group:
Chemistry
1 answer:
Leno4ka [110]3 years ago
7 0

Answer:

. 1. This amino acid has a positively charged R group: ARGININE

2. This amino acid has a negatively charged R group: ASPARTATE

3. This amino acid has a neutral polar R group: NONE

4. This amino acid has a nonpolar aliphatic R: VALINE

5. This amino acid has an aromatic R group: TRYTOPHAN

Explanation:

1) Arginine contains an extra amino group bearing a positive charge, in its chain which imparts basic properties to it

2) Aspartate contains an extra carboxyl group with a dissociable protron. Once the Protron is dissociated, it carries an extra negative charge in its side chain (R)

3) NONE of the amino acids given belong to this group because amino acids with neutral polar R groups contain functional groups that form hydrogen bonds with water. But, this is not the case with tryptophan aspartate valine or arginine

4) Valine has a R group that is hydrocarbon in nature and thus hydrophobic.

5) Trytophan has a benzene ring in its side chain

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Green plants use light from the Sun to drive photosynthesis, a chemical reaction in which liquid water and carbon dioxide gas fo
Luda [366]

Answer:

0.800 mol of O2

Explanation:

<em>Calculate the moles of oxygen produced by the reaction of 0.800mol of carbon dioxide.</em>

The balanced equation for the reaction is given as;

6CO2 + 6H2O → C6H12O6 + 6O2  

From the reaction;

6 mol of CO2 produces 6 mol of O2

0.0800 mol of CO2 would produce x mol of O2

6 = 6

0.0800 = x

Solving for x;

x = 6 * 0.800 / 6

x = 0.800 mol

5 0
2 years ago
Calculate the volume of dry co2 produced at body temperature (37 ∘c) and 0.970 atm when 25.5 g of glucose is consumed in this re
katrin2010 [14]

I believe the balanced chemical equation is:

C6H12O6 (aq) + 6O2(g) ------> 6CO2(g) + 6H2O(l) 

 

First calculate the moles of CO2 produced:

moles CO2 = 25.5 g C6H12O6 * (1 mol C6H12O6 / 180.15 g) * (6 mol CO2 / 1 mol C6H12O6)

moles CO2 = 0.8493 mol

 

Using PV = nRT from the ideal gas law:

<span>V = nRT  / P</span>

V = 0.8493 mol * 0.08205746 L atm / mol K * (37 + 273.15 K) / 0.970 atm

<span>V = 22.28 L</span>

6 0
3 years ago
A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0-L vessel at 300 K. The following equilibriu
tatyana61 [14]

Answer:

[H2] =    0.012 M

[N2] =    0.019 M

[H2O] =  0.057 M

Explanation:

The strategy here is to account for the species at equilibrium given that the concentration of [NO]=0.062M at equilibrium is known and the quantities initially present and its stoichiometry.

                  2NO(g)         +    2H2(g)    ⇒        N2(g)      +         2H2O(g)

i  mol            0.10                   0.050                                             0.10

c mol            -0.038                -0.038                +0019                +0.038                                                

e mol            0.062                 0.012                  00.019               0.057

Since the volume of the vessel is 1.0 L, the concentrations in molarity are:

[NO] =   0.062 M

[H2] =    0.012 M

[N2] =    0.019 M

[H2O] =  0.057 M

5 0
3 years ago
URGENT! 15 POINTS, WILL MARK BRAINLIEST
Virty [35]

Answer:

Explanation:

A. Linear Relationships

x 2     4       6       8     10     12

y 4.4  8.8  13.2  17.6   22  26.4

(you can plot this by using the (x,y) coordinates for each pair above.)

B. y=2.2x

mass is 2.2 times larger than the volume.

C. The mass is 2.2 times the volume.

3 0
3 years ago
Please help me with this homework
ella [17]

Answer:

Density is the correct answer choice.

5 0
3 years ago
Read 2 more answers
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