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Rudik [331]
2 years ago
14

But please I need this answer fast and if you don't know it don't answer it D.​

Chemistry
1 answer:
vampirchik [111]2 years ago
8 0

Answer:

its just a chromosome getting ready to split in a cell, Its called the telophase and its copying itself for the mother and daughter cell

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Pls help! Will mark brainliest! 55 Points!​
GenaCL600 [577]

Answer:

7cm square is the answer

Hope it's helpful

6 0
2 years ago
Read 2 more answers
At STP, solid carbon can exist as graphite or as diamond. These two forms of carbon have(1) the same properties and the same cry
Umnica [9.8K]
Answer=4

Diamonds and graphite have different properties and different crystal structures.

In diamonds, the carbon atoms are arranged tetrahedrally, whereas carbon atoms are arranged in an infinite array in graphite. Graphite has a lower density than diamonds... Diamonds are the best conductor of heat that we know of... the properties differ greatly 
3 0
2 years ago
The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because?.
Daniel [21]

The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because. it is the rate-limiting step

<h3>What is phosphorylation?</h3>

The first step in the metabolism of carbohydrates is frequently their phosphorylation. Because the phosphate group stops the molecules from migrating back across the transporter, phosphorylation enables cells to store carbohydrates. Glucose phosphorylation is a crucial step in the metabolism of sugar. In the first phase of glycolysis, D-glucose is converted to D-glucose-6-phosphate using the chemical equation D-glucose + ATP D-glucose-6-phosphate + ADP G° = 16.7 kJ/mol (° signifies measurement under standard conditions).

The rate-limiting stage in the liver's metabolism of glucose is the initial rate of phosphorylation of glucose (ATP-D-glucose 6-phosphotransferase) and non-specific hexokinase. Hepatic cells are freely permeable to glucose (ATP-D-hexose 6-phosphotransferase).

encouraging certain glucose transporters to translocate to the cell membrane.

To learn more about phosphorylation from the given link:

brainly.com/question/2138188

#SPJ4

7 0
1 year ago
Which is NOT an example of plants demonstrating the characteristics of life?
Lena [83]

Answer:

D

Explanation:

trust me bro ive done this

3 0
3 years ago
Calculate the number of moles in 3.01 x 1024 atoms of Krypton.
Kaylis [27]

Answer:

So 3.01×10236.022×1023mol−1 is clearly 1/2 a mole of silicon atoms. You should be quickly able to tell me the mass of this quantity of silicon atoms.

I think or 1/3 a mole Id k I’m just starting to learn this ok

Explanation:

6 0
3 years ago
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