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Len [333]
2 years ago
12

Find the molarity of a 500 L solution that contains 10 moles of fluorine.

Chemistry
1 answer:
deff fn [24]2 years ago
3 0

<u>Given </u><u>:</u><u>-</u>

  • Number of moles = 10
  • Volume of solution = 500L

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • Molarity of the solution .

<u>Solution</u><u> </u><u>:</u><u>-</u>

As we know that ,

\longrightarrow Molarity (M )=\dfrac{Number\ of \ moles \ of \ solute }{Volume\ of \ solution\ (in \ L) }

Substitute ,

\longrightarrow M =\dfrac{10}{500L}

Simplify,

\longrightarrow M = \dfrac{1}{50}

Convert into decimal ,

\longrightarrow \underline{\underline{ M = 0.02 \ mol \ L^{-1}}}

This is the required answer .

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The element is silicon (Si). It forms minerals like quartz and rocks such as granite.

5 0
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From a cross between a short-haired guinea pig (hh) and a long-haired guinea pig (Hh), what would be the possible phenotypes of
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Answer:

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Explanation:

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5 0
3 years ago
What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)
lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

\Delta T = i \times Kf \times m =   1 \times 6.90 \°C/m  \times 1.324m = 9.14  \°C

where,

  • i: van 't Hoff factor (1 for non-electrolytes)
  • Kf: cryoscopic constant
  • m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

T = 80.26 \° C - 9.14 \° C = 71.12 \° C

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

3 0
2 years ago
Sixty-five percent of the mass of bone is a compound called hydroxyapatite. sixty-five percent of the mass of bone is a compound
mafiozo [28]
True. Its simple how i remeberd was the bone has 650,000 cells and the bone has 65% hydroxyapatite
5 0
2 years ago
How many grams are in 3.14 moles of PI₃?
OverLord2011 [107]

Answer:

\boxed {\boxed {\sf 1290 \ g \ PI_3}}

Explanation:

We want to convert from moles to grams, so we must use the molar mass.

<h3>1. Molar Mass</h3>

The molar mass is the mass of 1 mole of a substance. It is the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We are given the compound PI₃ or phosphorus triiodide. Look up the molar masses of the individual elements.

  • Phosphorus (P): 30.973762 g/mol
  • Iodine (I): 126.9045 g/mol

Note that there is a subscript of 3 after the I in the formula. This means there are 3 moles of iodine in 1 mole of the compound PI₃. We should multiply iodine's molar mass by 3, then add phosphorus's molar mass.

  • I₃: 126.9045 * 3=380.7135 g/mol
  • PI₃: 30.973762 + 380.7135 = 411.687262 g/mol

<h3>2. Convert Moles to Grams</h3>

Use the molar mass as a ratio.

\frac {411.687262 \ g \ PI_3}{ 1 \  mol \ PI_3}

We want to convert 3.14 moles to grams, so we multiply by that value.

3.14 \ mol \ PI_3 *\frac {411.687262 \ g \ PI_3}{ 1 \  mol \ PI_3}

The units of moles of PI₃ cancel.

3.14 *\frac {411.687262 \ g \ PI_3}{ 1 }

1292.698 \ g\ PI_3

<h3>3. Round</h3>

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the tens place.

  • 1292.698

The 2 in the ones place tells us to leave the 9.

1290 \ g \ PI_3

3.14 moles of phosphorous triiodide is approximately equal to <u>1290 grams of phosphorus triodide.</u>

4 0
2 years ago
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