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3 years ago

Is mass is 88.2 and height of distance is 25m, how do you find speed?

Physics

1 answer:

Natasha_Volkova [10]3 years ago

4 0

Answer:

The velocity will be v = 22.1[m/s]

Explanation:

We can solve this problem by using the principle of energy conservation, where potential energy is converted to kinetic energy. For this problem we will take the point with maximum potential energy when the body is 25 [m] high. By the time the height is zero, the potential energy will have been transformed into kinetic energy, and we can find the velocity of the body.

$Ep = m*g*h\\where:\\m = mass = 88.2[kg]\\h = elevation = 25[m]\\g = gravity = 9.81 [m/s^2]\\Ep = 88.2*25*9.81 = 21631.05[J]\\$

Now we know that the energy will be transformed.

$Ek=Ep\\Ek=0.5*m*v^{2} \\where:\\v=velocity [m/s]\\v=\sqrt{\frac{Ek}{0.5*m} } \\v=\sqrt{\frac{21631.05}{0.5*88.2} } \\v=22.14[m/s]$

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DESPERATEA rocket of mass 40 000 kg takes off and flies to a height of 2.5 km as its engines produce 500 000 N of thrust.

jek_recluse [69]

Answer:

i=1250000000j

ii=

Explanation:

i . Energy= force × distance

= 500000N × 2500m

= 1250000000j

ii . Force = mass × acceleration

500000N= 40000kg × a

500000÷40000= 12.5m/s^2

S=1/2at^2

2500m=1/2×12.5×t^2

2500m=6.25 ×t^2

2500÷6.25=400

400= t^2

√400= √t^2

t = 20seconds

Speed= distance ÷ time

= 2500÷20

= 125m/s

5 0

3 years ago

A system of mass 13 kg undergoes a process during which there is no work, the elevation decreases by 50 m, and the velocity incr

marin [14]

Answer:

The change in kinetic energy is 4.3875 kJ

The amount of energy transferred by heat for the process is -66.98 kJ

Explanation:

Given;

mass of the system, m = 13 kg

change in height, Δh = -50 m

initial velocity, u = 15 m/s

final velocity, v = 30 m/s

change in internal energy per mass, ΔU = -5 kJ/kg

The change in kinetic energy is given by;

ΔK.E = K.E₂ - K.E₁

ΔK.E = ¹/₂mv² - ¹/₂mu²

ΔK.E = ¹/₂m(v² - u²)

ΔK.E = ¹/₂ ₓ 13 (30² - 15²)

ΔK.E = 4387.5 J

ΔK.E = 4.3875 kJ

The amount of energy transferred by heat for the process;

Q = W + ΔP.E + ΔK.E + ΔU

Where;

ΔP.E = mgΔh

ΔP.E = 13 x 9.8 x (-50)

ΔP.E = -6370 J = -6.37 kJ

W = 0

ΔU = -5kJ/kg x 13kg

ΔU = -65 kJ

Q = W + ΔP.E + ΔK.E + ΔU

Q = 0 + (-6.37) + (4.3875) + (-65)

Q = -66.98 kJ

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4 years ago

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different len

WARRIOR [948]

For the different wires the values given are

For Wire A, Area= $A_{A}$ , Resistivity= $ρ_{A}$ , Length= $L_{A}$ , Heat= $H_{A}$ , Voltage= V, Time= t, Wire B, Area= $A_{B}$ , Resistivity= $ρ_{B}$ , Length= $L_{B}$ , Heat= $H_{B}$

So, $H_{A}$ / $H_{A}$ = $\frac{V^{2} *t}{\frac{ρ(1)*L_{A} }{A_{A} } }$ / $\frac{V^{2} *t}{\frac{ρ(2)*L_{B} }{A_{B} } }$

Therefore $H_{A}$ / $H_{A}$ = $\frac{A_{A}*ρ_{B} *L_{B}}{A_{B}ρ_{A} L_{A} }$

The type of energy that moves between two materials with varying temperatures is referred to by scientists as heat. Because the average translational kinetic energy per molecule in the two materials varies, an energy transfer takes place. Up until thermal equilibrium is attained, heat is transferred from the substance with the higher temperature to the material with the lower temperature. The joule, with 1 joule equalling 1 newton meter, is the SI unit of heat. Imagine the following situation to better comprehend what happens when this energy transfer takes place: Tiny rubber balls are bouncing all over two distinct containers that are full with them. The difference between the average ball speed in one container and the second container is substantial.

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters

Learn more about heat here:

brainly.com/question/21041726

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2 years ago

A car traveling in a straight line has a velocity of +4.4 m/s. after an acceleration of 0.65 m/s2 , the car's velocity is +8.3 m

nydimaria [60]

Answer:

1.53seconds

Explanation:

Using first equation of motion :

V=U + at

Where final velocity (V) =+8.3m/s

Initial velocity (U) =+4.4m/s

Acceleration (a) = 0.65m/s^2

time(s)=?

V=U + at

+8.3^2 = +4.4 + 0.65 * t

Making t the subject of the formula :

Therefore, t= ( +8.3 - 4.4)/0.65 = 1.53seconds

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4 years ago

At the beginning of a basketball game, a referee tosses the ball straight up with a speed of 4.6 m/s. a player cannot touch the

-Dominant- [34]

At the beginning of a basketball game, a referee tosses the ball straight

up with a speed of 4.6 m/s. a player cannot touch the ball until after it reaches its maximum height and begins to fall down. what is the minimum time that a player must wait before touching the ball? s

-----------------------

kinemaic equation

v=u-at

0=4.6-9.81xt

t=4.6/9.81 ... about half a second

4 0

3 years ago