The football and air resistance between contact
Answer:
692.31 N
Explanation:
Applying,
F = ma............... Equation 1
Where F = Average force required to stop the player, m = mass of the player, a = acceleration of the player
But,
a = (v-u)/t............ Equation 2
Where v = final velocity, u = initial velocity, t = time.
Substitute equation 2 into equation 1
F = m(v-u)/t............ Equation 3
From the question,
Given: m = 75 kg, u = 6.0 m/s, v = 0 m/s (to stop), t = 0.65 s
Substitute these values into equation 3
F = 75(0-6)/0.65
F = -692.31 N
Hence the average force required to stop the player is 692.31 N
The volume of the object must be no larger than
.
Explanation:
In order for an object to be able to float in water, its density must be equal or smaller than the water density.
The density of water is:

This means that the density of the object must be no larger than this value.
We also know that the density of an object is given by

where
m is the mass of the object
V is its volume
For the object in this problem, the mass is

Therefore, we can re-arrange the equation to find its volume:

So, the volume of the object must be no larger than
.
Learn more about density:
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Using the same antenna. Now he doesn't know if it was the antenna that caused the change in reception. so he wasn't only measuring the reception in his house he was measuring it based on different antennas