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timurjin [86]
3 years ago
15

Which of the elements below has the highest ionization energy? Carbon, calcium, barium, or fluorine?

Chemistry
1 answer:
Serjik [45]3 years ago
6 0
Fluorine has 1680 kJ/mol
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Which statement is true about the exothermic reaction?
Stells [14]

Answer:

C

Explanation:

The enthalpy of the reactants is greater than that of the products.

7 0
2 years ago
212 pb 82 is the isotope notation for iron. what is the atomic number, mass number, and number of both protons and neutrons?
o-na [289]

Hello!

The mass number in isotope notation is denoted A, the atomic number is denoted as Z, and the element is denoted as X.

In the given isotope, the mass of the isotope is 212 amu, and the atomic number is 82.

We know that the number of electrons, and protons are equal to the atomic number. Therefore, there are 82 protons. Also, to find the number of neutrons, we subtract the atomic number from the atomic mass.

212 - 82 = 130 neutrons

<u>Final answers</u>:  

  1. Atomic Number: 82
  2. Mass number: 212
  3. Number of Protons: 82
  4. Number of Neutrons: 130
5 0
3 years ago
Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find
FromTheMoon [43]

<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

4 0
3 years ago
Miles and pounds are use in which systems?
lisabon 2012 [21]

Answer:

The United States customary system aka USCS or USC?

4 0
3 years ago
Lithium carbonate, li2co3, contains 18.8 % lithium and is used in the treatment of mental illnesses such as bipolar disorder. wh
masha68 [24]
Assuming that the percentage composition is on the basis of weight percentage, therefore the mass of lithium would simply be the product of the two, that is:
mass Lithium = 0.188 * 1.70 g
mass Lithium = 0.3196 g = 0.32 g
5 0
3 years ago
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