Answer: Thus concentration of
in
is 0.011 and in
is 0.814
Explanation:
To calculate the concentration of
, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is 
We are given:

Putting values in above equation, we get:

The concentration in
is 
Thus concentration of
is
and 
Assuming its at r. t.p and pressure
no. of moles = 96/24=4moles
altho some books will say that its 23.7dm3/mole but that doesnt really matter because its the process that matters
Triglyceride is a molecule constituted by one one molecule of glycerol and 3 molecules of fatty acids. The structure of a glycerol is like a letter "E", where the vertical line ( | ) is the glycerol and the three horizontal lines are long chains of organic acids, each with one COOH group, called fatty acids.<span> The answer is that the other 3 molecules that make up a triglyceride are fatty acids.</span>
Explanation:
We have to calculate
value.
It is known that at the equivalence point concentration of acid is equal to the concentration of anion formed.
Hence, [HA] = ![[A^{-}]](https://tex.z-dn.net/?f=%5BA%5E%7B-%7D%5D)
Now, relation between
and pH is as follows.
pH = ![pK_{a} + log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
Putting the values into the above formula as follows.
pH = ![pK_{a} + log \frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
4.23 =
(as [HA] =
)
= 4.23 (as log (1) = 0)
or,
= 4
Thus, we can conclude that
of given weak acid is 4.
Substitution Reactions are those reactions in which one nucleophile replaces another nucleophile present on a substrate. These reactions can take place via two different mechanism i.e SN¹ or SN². In SN¹ substitution reactions the leaving group leaves first forming a carbocation and nucleophile attacks carbocation in the second step. While in SN² reactions the addition of Nucleophile and leaving of leaving group take place simultaneously.
Example:
OH⁻ + CH₃-Br → CH₃-OH + Br⁻
In above reaction,
OH⁻ = Incoming Nucleophile
CH₃-Br = Substrate
CH₃-OH = Product
Br⁻ = Leaving group
Organic reactions are typically slower than ionic reactions because in organic compounds the covalent bonds are first broken, this breaking of bonds is a slower step, while, in ionic compounds no bond breakage is required as it consists of ions, so only bond formation takes place which is a quicker and fast step.