Answer:
Reactants and products
Explanation:
The reaction can be writen inthis way
⇒
Here we can notice that water and carbon dioxide are combined, so they are the reactants and produce glucose and oxygen that are the products.
The strumming is mechanical energy
the notes heard is sound energy
so use D
In NaMnO₄, Mn has the highest oxidation number.
The question is incomplete, the complete question is;
Which of the following species contains manganese with the highest oxidation number?
A) Mn
B) MnF₂
C) Mn₃(PO₄)₂
D) MnCl₄
E) NaMnO₄
In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.
1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.
2) For MnF₂;
Mn has an oxidation number of +2
3) For Mn₃(PO₄)₂
Mn has an oxidation number of +2
4) For MnCl₄
Mn has an oxidation number of +4
5) For NaMnO₄
Mn has an oxidation number of +7
Hence in NaMnO₄, Mn has the highest oxidation number.
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Answer:
A wave transfers energy through a medium or empty space without transporting matter.
Explanation:
- A wave is a transmission of a disturbance from one point known as the source to another.
- Waves may transfer energy through a material medium or a vacuum without transporting matter.
- Waves that transfer energy from one point to another through a material medium are known as mechanical waves.
- Electromagnetic waves, on the other hand, are those that do not require a material medium for transmission, the transfer of energy is through a vacuum.
- Waves can also be either transverse or longitudinal waves based on the vibration of particles relative to the direction of wave motion.
The required volume of water is 0.18 liters.
<h3>What is molarity?</h3>
Molarity of any solution is define as the number of moles of solute present in per liter of solution as;
M = n/V
Moles of solute will be calculated as:
n = W/M, where
W = given mass of HCl = 32g
M = molar mass of HCl = 36.4g/mol
n = 32 / 36.4 = 0.88 mole
Given molarity of solution = 4.80M
On putting all values in the above equation, we get
V = (0.88) / (36.4) = 0.18 L
Hence required volume of water is 0.18L.
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