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r-ruslan [8.4K]
3 years ago
9

What coefficients would balance the following equation?

Chemistry
1 answer:
Alla [95]3 years ago
7 0
4Al + 3O2 —> 2AL2O3
Answer is D
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#76 <br> Filllllllllllllllllllllllllllllller
kobusy [5.1K]
Atomic Mass = 140.1 amu

Element= Ce (Cerium)
5 0
3 years ago
calculate the number of coulombs of positive charge in 250cm 3 of (neutral) water. (hint: a hydrogen atom contains one proton; a
Sidana [21]

Number of coulombs of positive charge in 250cm^3 water is 1.3×10^7 C

The volume of 250 cm^3 corresponds to a mass of 250 g since the density of water is 1.0 g/cm^3

This mass corresponds to 250/18 = 14 moles since the molar mass of water is 18. There are ten proton (each with charge q = +e) in each molecule of H_{2}O So,

Q = 14NA  q =14(6.02×10^23)(10)(1.60×10^−19C) = 1.3×10^7 C.

Mass is the quantity of matter in a physical body. It is also a measure of the body's inertia, the resistance to acceleration when a net force is applied. An object's mass also determines the strength of its gravitational attraction to other bodies.

Learn more about mass here:

brainly.com/question/17067547

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3 0
2 years ago
Compute the percentage of error to the nearest tenth in the student’s calculation if the actual specific heat value for aluminum
Artist 52 [7]

Complete Question:

1. A block of aluminum with a mass of 140 g is cooled from 98.4°C to 62.2°C with a release of 4817 J of heat. From these data, calculate the specific heat of aluminum.

a. Compute the percentage of error to the nearest tenth in the student's calculation if the actual specific heat value for aluminum is 0.9 J/g°C

Answer:

Percent error = 55.56 %

Explanation:

Given the following data;

Mass = 140 grams

Initial temperature = 62.2°C

Final temperature = 98.4°C

Quantity of heat = 4817 Joules.

To find the specific heat capacity;

Heat capacity is given by the formula;

Q = mcdt

Where;

  • Q represents the heat capacity or quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity of water.
  • dt represents the change in temperature.

dt = T2- T1

dt = 98.4 - 62.2

dt = 36.2°C

Making c the subject of formula, we have;

c = \frac {Q}{mdt}

Substituting into the equation, we have;

c = \frac {4817}{140*36.2}

c = \frac {4817}{5068}

<em>Specific heat capacity, = 0.95 J/g°C</em>

b. To find the percentage error;

Given the following data;

Actual specific heat capacity = 0.9 J/g°C

Experimental specific heat capacity = 0.95 J/g°C

Percent error can be defined as a measure of the extent to which an experimental value differs from the theoretical value.

Mathematically, it is given by this expression;

Percent \; error = \frac {experimental \;value - actual \; value}{ actual \;value} *100

Substituting into the formula, we have;

Percent \; error = \frac {0.95 - 0.9 }{ 0.9} *100

Percent \; error = \frac {0.5}{0.9} *100

Percent \; error = 0.5556 *100

<em>Percent error = 55.56 %</em>

5 0
3 years ago
The conversion of glucose-6-phosphate to fructose-6-phosphate is catalyzed by an isomerase enzyme. Glucose-6-phosphate was mixed
harkovskaia [24]

Answer: the equilibrium is 0.667 M

5 0
4 years ago
Iron-56, Iron-54, and Iron-58 are all ____ of iron
JulijaS [17]

Answer:

in the 50 place

Explanation:

3 0
4 years ago
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