Answer:
a) 0.069 acres
b) 0.114acres
c) 17.78acres
Explanation:
1 dot=1/36sqin
a) 1 sqin= 330×330=108900ft^2
1 dot=108900/36 =3025ft^2
Converting to acre,divide by43560
3025/43560 =0.069acre
b) 1 chain =22 yards
25×22=550yards
Converting to acre divide by 4840
550/4840 =0.114acre
c)1 sqmile =640acres
(1/36) ÷ 640
640/36
17.78acres
Answer:
As we navigate down a group the atoms get bigger and bigger with more and more electrons. This means the outermost electrons get further and further away from the positively charged nucleus.
This composition from Ni and Cu is called cupronickel.It is high in copper and silver in colour and highly resistant to corrosion, particularly seawater. Cooper nickel is used in the industry, in marine engineering . Melting point is 2254,73 F, which is 1234.85 Celsius. In this range of tempereature the cupronickel melts.
Answer:
a = 0 m/s²
Explanation:
given,
car moving at steady velocity = 100 Km/h
1 km/h = 0.278 m/s
100 Km/h = 27.8 m/s
time of acceleration = 100 s
acceleration is equal to change in velocity per unit time.

change in velocity of the car is 27.8 - 27.8 = 0

a = 0 m/s²
If the car is moving with steady velocity then acceleration of the car is zero.
Hence, the acceleration of the car is equal to a = 0 m/s²
Answer:
0.785 m/s
Explanation:
Hi!
To solve this problem we will use the equation of motion of the harmonic oscillator, <em>i.e.</em>
- (1)
- (1)
The problem say us that the spring is released from rest when the spring is stretched by 0.100 m, this condition is given as:


Since cos(0)=1 and sin(0) = 0:


We get

Now it say that after 0.4s the weigth reaches zero speed. This will happen when the sping shrinks by 0.100. This condition is written as:

Since

This is the same as:

We know that cosine equals to -1 when its argument is equal to:
(2n+1)π
With n an integer
The first time should happen when n=0
Therefore:
π = 0.4ω
or
ω = π/0.4 -- (2)
Now, the maximum speed will be reached when the potential energy is zero, <em>i.e. </em>when the sping is not stretched, that is when x = 0
With this info we will know at what time it happens:

The first time that the cosine is equal to zero is when its argument is equal to π/2
<em>i.e.</em>

And the velocity at that time is:

But sin(π/2) = 1.
Therefore, using eq(2):

And so:
