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lozanna [386]
3 years ago
8

How many joules are needed to warm 65.6 grams of water from 14ºC to 22.5ºC?

Chemistry
1 answer:
Ahat [919]3 years ago
7 0

Answer:

2334.1136 Joules

Explanation:

Q= 65.6 g (4.186)(8.5)

If it's suppose to be in kilograms, the answer will be 2.3341136 Joules.

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Answer:

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A sample of gas occupies a volume of 50.0 milliliters in a cylinder with a movable piston. The pressure of the sample is 0.90 at
solong [7]

Answer:

The volume of sample at STP is = 41.22 ml

Explanation:

Given data

P_{1} = 0.9 atm

V_{1} = 50 ml

T_{1} = 298 K

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P_{2} = 1 atm

T_{2} = 273 K

From ideal gas equation

\frac{P_1(V_1)}{T_1} = \frac{P_2(V_2)}{T_2}

\frac{(0.9)(50)}{298} = \frac{(1) V_2}{273}

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Oxygen is most chemically similar to <br>Anitrogen <br>Bsulfur <br>Cfluorine​
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3 years ago
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(1.) Using Beer's Law, How will the absorbance measured for the solutions change as the concentration of aspirin in solutions in
Vesnalui [34]

Answer:

(1) The absorbance of the aspirin in solutions will increase.

(2) [ASA]f = 3.79x10⁻⁴M

(3) [ASA]i = 3.79x10⁻³M

(4) m ASA = 0.171g

Explanation:

<u>The Beer's Law is expressed by:</u>

A = \epsilon \cdot l \cdot C (1)

<em>where A: is the absorbance of the species, ε: is the molar attenuation coefficient, l: is the pathlength and C: is the concentration of the species</em>

(1) <u>From </u><u>equation (1)</u><u>, the relation between the absorbance of the species and its concentration is directly proportional,</u> so if the aspirin concentration in solutions increases, the absorbance of the solutions will also increase.

(2) Starting in the given expression for the relationship between absorbance and concentration of ASA, we can calculate its concentration in the solution:

A = 1061.5 \cdot [ASA]    

[ASA] = \frac{A}{1061.5} = 3.79 \cdot 10^{-4}M

Therefore, the aspirin concentration in the solution is 3.79x10⁻⁴ M

(3) To calculate the stock solution concentration, we can use the next equation:

V_{i} [ASA]_{i} = V_{f} [ASA]_{f}

<em>where Vi: is the stock solution volume=10mL, Vf: is the solution diluted volume=100mL, [ASA]i: is the aspirin concentration of the stock solution and [ASA]f: is the aspirin concentration of the diluted solution</em>

[ASA]_{i} = \frac{V_{f} \cdot [ASA]_{f}}{V_{i}} = \frac {100mL \cdot 3.79\cdot 10^{-4} M}{10mL} = 3.79 \cdot 10^{-3} M

Hence, the concentration of the stock solution is 3.79x10⁻³M

(4) To determine the aspirin mass in the tablet, we need to use the following equation:

m_{ASA} = \eta_{ASA} \cdot M_{ASA} = [ASA]_{i} \cdot V_{0} \cdot M_{ASA}

<em>where η: is the aspirin moles = [ASA]i V₀, M: is the molar mass of aspirin=180.158g/mol, V₀: is the volume of the volumetric flask=250mL and [ASA]i: is the aspirin concentration in the volumetric flask which is equal to the stock solution=3.79x10⁻³M</em>

m_{ASA} = 3.79 \cdot 10^{-3} \frac{mol}{L} \cdot 0.250L \cdot 180.158 \frac{g}{mol} = 0.171 g  

Then, the aspirin mass in the tablet is 0.171 g.

I hope it helps you!

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Exactly what the person above me said
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